Distributive property

Bas_tet [7]

It’s phrased very weird, but I believe I have it figured out.

On the map, there distance of the race is 41.9 inches.

So, (41.9)(400) = 16760 feet

8 0

3 years ago

Which of the following is not true about cluster sampling?

Aloiza [94]

Answer:

The correct answer is D. It is not true that cluster sampling uses randomly selected clusters and samples everyone within each cluster.

Step-by-step explanation:

Cluster sampling is a method of collecting samples and statistical data, by means of which a certain group formed by people, things, events, etc., is taken as a sample, which are not considered individually but as part of a whole, which is in turn a proportional representation of the universality of samples available in the field.

Now, since this type of sampling allows to embrace large groups of sample units, data are not always obtained from all the components of the cluster, but from those necessary to be able to quantify the desired statistics.

5 0

2 years ago

Read 2 more answers

Which equation is y=(x+3)2+(x+4)2 rewritten in vertex form

Julli [10]

Vertex coordinates: (h, k)

Vertex form: y = a(x-h)^2 + k

y = 2(x+3) + 2(x+4)

Use distributive property:

y = 2((x+3)+(x+4))

Simplify:

y = 2(2x+7)

y = 4x+14

This is slope - intercept form, not vertex form. Vertex form is for quadratic equations - this is a linear equation.

Answer (in slope - intercept form):

y = 4x+14

3 0

3 years ago

10(a-2.5+0.56b) is this equivalent to 10a - 25+56b

kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

2 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago