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vitfil [10]
3 years ago
5

I need help with solving this question with the elimination method since my teacher didn’t explain lol

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

*itccyohchcuvojvibbib

there u go :)

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What is the answer for 1-2...please show how you got the answer....thank you
GrogVix [38]
1=650,000
2=270,000
_____________________________________________________________
Redstar215
3 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
- Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the northbound
PIT_PIT [208]

Answer:

Step-by-step explanation

Use Pythagoras theorem. The distance between the cars, 8km, is the hypotenuse of a right angled triangle, one leg of which is 6km and the other of which is, say, x km

x = sqrt(8^2 - 6^2) km.

You can crunch the numbers.

4 0
2 years ago
Find the linear equation in slope intercept form that passes through the points (5,3) and (2,-1)
padilas [110]

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{3})\qquad  (\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-3}{2-5}\implies \cfrac{-4}{-3}\implies \cfrac{4}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{4}{3}(x-5)\implies y-3=\cfrac{4}{3}x-\cfrac{20}{3} \\\\\\ y=\cfrac{4}{3}x-\cfrac{20}{3}+3\implies y=\cfrac{4}{3}x-\cfrac{11}{3}

8 0
3 years ago
Read 2 more answers
Given that f(x) = x2 – 3x – 28 and g(x) = x - 7, find
gregori [183]

Answer:

(f-g)(x)=x^2-4x-21

Step-by-step explanation:

We are given the two functions:

f(x)=x^2-3x-28\text{ and } g(x)=x-7

And we want to find:

(f-g)(x)

This is equivalent to:

=f(x)-g(x)

Substitute:

=(x^2-3x-28)-(x-7)

Distribute:

=x^2-3x-28-x+7

Rearrange:

=(x^2)+(-3x-x)+(-28+7)

Hence:

(f-g)(x)=x^2-4x-21

6 0
2 years ago
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