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emmainna [20.7K]
3 years ago
14

Four-fiths of Zack’s stamps have pictures of animals. How many stamps with pictures of animals does Zack have?

Mathematics
1 answer:
NARA [144]3 years ago
8 0

Answer:

Four

Step-by-step explanation:

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At the start of a tennis match Ivan had 28/32 quart of water in his water bottle. He drank water from the bottle during the matc
const2013 [10]

Answer:

5/8 of a quart.

Step-by-step explanation:

That would be 28/32 - 1/4

= 28/32 - 8 /32

= 20/32  

= 5/8 of a quart.

5 0
3 years ago
The coordinates of point Care<br> A. (3,-1)<br> B. (1, -3)<br> C. (3,1)<br> D. (-3,1)<br> E. (-3,-1)
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D (-3,1) hopes this helps
4 0
2 years ago
8. Solve for x. Round your answer to the nearest tenth.<br> 8.6<br> 4<br> x<br> 0176
earnstyle [38]

Answer:

C. 9.5

Step-by-step explanation:

The Pythagorean Theorem: a^2 + b^2 = c^2.

4^2 + 8.6^2 = c^2

16 + 73.96 = c^2

c^2 = 89.96

c = 9.4847....

8 0
2 years ago
3[(15 - 3) squared divided by 4]
Ronch [10]
<span>3[(15 - 3) squared divided by 4]
=</span><span>3[(15 - 3)^2 / 4]
=3</span>[(12)^2 / 4]
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8 0
3 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
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