Plz help, it is mathswatch
1 answer:
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A. It's a composite function, so basically, wherever you see a p, replace it with 5t, because we are given that information. So, your answer is:
![A[p(t)] = 5t \pi 2=10t \pi](https://tex.z-dn.net/?f=A%5Bp%28t%29%5D%20%3D%205t%20%5Cpi%202%3D10t%20%5Cpi%20)
B. Let's use the function we created, and just plug in 2 for t:
![A[p(2)] = 10(2) \pi](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%20%3D%2010%282%29%20%5Cpi%20)
![A[p(2)] = 62.83](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%3D%2062.83)
So, your answer is (approximately) 62.83 units².
B. Let's use the function we created, and just plug in 2 for t:
So, your answer is (approximately) 62.83 units².
Answer:
Sum of the solutions of is -9.
Product of the solutions of is
Step-by-step explanation:
1.
Given:
The expression whose sum of the solution is required is given as:
For a quadratic equation of the form the sum of the solutions is given as:
Sum =
Here,
Therefore, the sum of the solutions =
2.
Rewriting the above equation in a standard quadratic equation, we get:
For a quadratic equation of the form the product of the solutions is given as:
Product =
Here,
Therefore, the product of the solutions =