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suter [353]
3 years ago
15

0.70 g of hydrogen chloride (HCl) is dissolved in water to make 5.0 L of solution. What is the pH of the resulting hydrochloric

acid solution? Express the pH numerically to two decimal places.
Chemistry
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

( About ) 2.42 pH

Explanation:

First convert grams to mole of the hydrochloric acid,

HCl ( moles ) = 0.7g * ( 1 mole / 36.5g ),

0.7 / 36.5 = ( About ) 0.0192 moles

Now take the moles as a fraction over the given liters, to determine " M, " the apparent pH

M = 0.0192 mole / 5.0 L,

M = 0.00384M

_________________________________________________

Because HCl is a strong acid and will completely ionized, take a look at the steps below,

[ H+ ] = 0.00384M pH = -log[H+] = - log[0.00384],

- log[0.00384] = - ( - 2.41566... )

Solution = ( About ) 2.42 pH

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How many milliliters of 3.0M phosphoric acid can be made from 95mL of 5.0M solution?
zloy xaker [14]
Thats a tuff one ummmmmm 4.5 m

4 0
4 years ago
Match the symbol for each element with the name of the element. 1. hydrogen K 2. helium Mg 3. sodium He 4. magnesium H 5. potass
insens350 [35]

Answer:

1. hydrogen - H

2. helium - He

3. sodium - Na

4. magnesium - Mg

5. potassium - K

Explanation:

Hydrogen is the element of group 1 and first period. The atomic number of hydrogen is 1 and the symbol of the element is H.

The electronic configuration of the element hydrogen is:-

1s^1

Helium is the element of group 18 and first period. The atomic number of helium is 2 and the symbol of the element is He.

The electronic configuration of the element helium is:-

1s^2

Sodium is the element of group 1 and third period. The atomic number of sodium is 11 and the symbol of the element is Na.

The electronic configuration of the element sodium is:-

1s^22s^22p^63s^1

Magnesium is the element of group 2 and third period. The atomic number of magnesium is 12 and the symbol of the element is Mg.

The electronic configuration of the element magnesium is:-

1s^22s^22p^63s^2

Potassium is the element of group 1 and forth period. The atomic number of potassium is 19 and the symbol of the element is K.

The electronic configuration of the element potassium is:-

1s^22s^22p^63s^23p^64s^1

5 0
3 years ago
What describes the current model of an atom​
vladimir2022 [97]

Answer:

A tiny sense positively charge core called a nucleus in which nearly all the mass is concentratedm

8 0
3 years ago
An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with
Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

<u>Step 1:</u> The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

<u>Step 2:</u> Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

<u>Step 3: </u>Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

<u>Step 4: </u>Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

<u>Step 5: </u>Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

3 0
3 years ago
What is the energy of a photon that emits a light of frequency 6.42 x 1014 Hz?<br><br>​
svetlana [45]

Answer:

Option B. 4.25×10¯¹⁹ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 6.42×10¹⁴ Hz

Energy (E) =?

Energy and frequency are related by the following equation:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

With the above formula, we can obtain the energy of the photon as follow:

Frequency (f) = 6.42×10¹⁴ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 6.42×10¹⁴

E = 4.25×10¯¹⁹ J

Thus, the energy of the photon is 4.25×10¯¹⁹ J

3 0
3 years ago
Read 2 more answers
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