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raketka [301]
3 years ago
5

Which expression is equal to a + (b + c)?

Mathematics
2 answers:
rjkz [21]3 years ago
6 0

\huge{\boxed{(a+b)+c}}

For example, 2+(3+4)=2+7=9.

If we group the terms differently, it doesn't matter. (2+3)+4=5+4=9

This is called the associative property of addition. As long as you still have all of the terms, and there are no other operations (subtraction, multiplication, etc.), the final answer will remain the same no matter how the terms are grouped.

trasher [3.6K]3 years ago
4 0

Answer:

The correct option is (a+b)+c

Step-by-step explanation:

The correct option is (a+b)+c

According to the Associative property for Addition:

a+(b+c)=(a+b)+c

The associative property states that you can add or multiply regardless of how the numbers are grouped.

.If you are adding or multiplying it does not matter where you put parenthesis.

Thus the correct option is A....

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I think the answer is C
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PLEASE HELP FAST!! <br>1. Find x. Show your work.​
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Step-by-step explanation:

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7 0
2 years ago
Solve 9^x + 4 = 11 for x using the change of base formula log base b of y equals log y over log b.
Sauron [17]

Answer:

If you meant 9^x+4=11, then the answer is approximately 0.866.

If you meant 9^{x+4}=11, then the answer is approximately -2.909 which looks like what you meant based on the choices.

Step-by-step explanation:

9^x+4=11

First step is to get the exponential part by itself. The part that has the variable exponent which is the 9^x term.

To do this we need to subtract 4 on both sides:

9^x=11-4

Simplify:

9^x=7

The equivalent logarithmic form is:

\log_9(7)=x

I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.

Anyways if you don't have options for computing \log_b(a) in your calculator you need to use the change of base formula.

\frac{\log(7)}{\log(9)}=x

So x \approx 0.8856

I don't see this as a choice so maybe you actually meant the following equation:

9^{x+4}=11

Let's see if this is the correct interpretation.

So the exponential part is already isolated.

So we just need to put in the equivalent logarithmic form:

\log_9(11)=x+4

Now we subtract 4 on both sides:

\log_9(11)-4=x

Again if you don't have the option for computing \log_b(a) in your calculator, you will have to use the change of base formula:

\frac{\log(11)}{\log(9)}-4=x

x \approx -2.909

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3 years ago
1. Choose the best property to fill in the blank:
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Answer:

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Step-by-step explanation:


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3 years ago
H (x)=x^2-5<br> Find h (-7)
nalin [4]
H (-7) = (-7)^2 -5 = 49-5 = 44
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3 years ago
Read 2 more answers
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