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Kay [80]
3 years ago
14

Jerrilyn wrote the following argument to prove that

Mathematics
1 answer:
likoan [24]3 years ago
5 0

Answer:

absolutely no idea if this is right but i put the first one

Step-by-step explanation:

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What is the GFC of the numbers 12,18 and 26
guapka [62]
The greatest common factor (GCF) of 12, 18, and 26 is: 2

Since the lowest number is 12, you should only include factors up to 12.
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 18: 1, 2, 3, 6, 9
Factors of 26: 1, 2

The common factors between the three numbers are 1 and 2, but you are looking for the greatest common factor. The greatest means the highest, and which is the highest number out of 1 and 2? 2, so that is your answer.
3 0
3 years ago
Read 2 more answers
Plz someone help ASAP! thanks​
Papessa [141]

Answer:

B

Step-by-step explanation:

Because <u>at least </u>means not less than 50 or equal to 50

Since he wrote 18 pages then you have to add.

8 0
3 years ago
Triangle ABC was transformed using the rule (x, y) → (–y, x). The vertices of the triangles are shown. A (–1, 1) B (1, 1) C (1,
yaroslaw [1]

Answer:

the transformation was 90° at the origin

Step-by-step explanation:

the transformation was 90° at the origin

5 0
3 years ago
Read 2 more answers
How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup
Novay_Z [31]
New volume is given by:
New volume=(old volume)×(4×2/9×2/9)
simplifying the above we get:
New volume=(old volume)×16/81
Thus the new volume is 16/81 times the old volume
old volume=πr²h
Hence:
Answer:16/81πr²h


4 0
3 years ago
angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0
3 years ago
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