Answer:
The surface area of the net shown is: 88 
Step-by-step explanation:
Break up the different shapes in the net:
Let's take the big square first:
It has a side of 5in and a base of 4in.
We multiply both these values to get 20
Lets look at the small rectangular box now:
It has a side of 3in and a base of 4in.
We multiply both these values to get 12
There are two big squares so we add up their surface areas:
20 + 20 = 40
There are 4 small rectangular squares so we add up their surface areas:
12 + 12 + 12 + 12 = 48
Now we add up the big square and small rectangular squares values:
40 + 48 = 88
Therefore the answer is 88
Answer:d
Step-by-step explanation: just factor it out
I started this and got distracted and never finished and it timed out. Focus Dean.
It's not the best graph; I assume the origin is the apparent origin and the y axis numbers go with the line above them.
This graph is M(V), M(V) is mass in kg of bucket with water volume V in liters
a) the mass of an empty bucket
That's the y intercept, M(0), eyeballing it around .7 kg
Answer: .7 kg
b) the mass of the bucket containing 1 liter of liquid
That's M(1), looks like 1.3 or so
Answer: 1.3 kg
c) the mass of one liter of liquid
That's the difference, M(1)-M(0), about .6 kg. We can get a better estimate from a longer slope, say (.5,1) to (3,3), (3-1)/(3-.5) = .8 kg.
Answer
: 0.8 kg
d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg.
Solve M(V)=3
That has a solution from the graph V=3.
Answer: 3 liters
Answer:
0.25
Step-by-step explanation:
Given that a recently married couple are planning to have four children. They are equally likely to have a boy as well as a girl.
Let X be the no of boys the couples have. X has two outcomes with p = 0.5
X is binomial with n = no of trials = 4 and p =0.5
the probability that they will have three boys and one girl
=
Reqd prob = 0.25
