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3 years ago

How do I tell my mom that really this good

Mathematics

2 answers:

ZanzabumX [31]3 years ago

7 0

That what is good?

Have a good night

irina [24]3 years ago

4 0

Tell her that this app is really educational and helps you do better in school

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Solve each equation algebraically using if–then statements to justify each step 2(x + 4) = 8

Alex

This is what Photomath got

8 0

3 years ago

Vanessa and zack are playing a game where a player with the lower score wins at the end of the game Vanessa has a score of -3 5/

Novosadov [1.4K]

Complete question :

Vanessa and Zack are playing a game where the player with the lower score wins. At the end of the game, Vanessa has a score of -3 5/8 and Zack has a score of -3 2/3. Which statement explains who won?

Vanessa won. If you compare the decimal equivalents of their scores, -3.625 < -3.666.

Vanessa won. If you compare the decimal equivalents of their scores, -3.666 < -3.625.

Zack won. If you compare the decimal equivalents of their scores, -3.625 < -3.666.

Zack won. If you compare the decimal equivalents of their scores, -3.666 < -3.625

Answer: Zack won. If you compare the decimal equivalents of their scores, -3.666 < -3.625

Step-by-step explanation:

Given that :

Player with the lowest score wins ;

Vanessa's score = - 3 5/8

Zack's score = - 3 2/3

Converting to decimal:

Vanessa :

-3 5/8 = - 29 /8 = - 3.625

Zack:

-3 2/3 = - 11/3 = - 3.666

Comparing the scores :

From the negaryce side of a number line :

-3.666 comes before - 3.625, hence, - 3.666 is lower or lesser than - 3.625

-3.666 < - 3.625, hence Zack won

3 0

3 years ago

9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9

gladu [14]

Answer: a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

$x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)$

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

$\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976$