What is the equation in standard form of the line shown on the graph
2 answers:
Answer:
Step-by-step explanation:
We take two points (0,-3) and (4,0)
eq. of line thro' two points is y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)=(0+3)/(4-0)=3/4
Reqd. eq . is y-(-3)=3/4(x-0)
or y=3/4(x)-3
For this case we have that the standard equation of a line is given by:

Where:
m: It's the slope
b: It is the cut point with the y axis.

We have the following points of the graph:

Substituting:

We have:

To find the cut point we substitute a point:

Thus, the equation is:

Answer:

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