Answer:
The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.
Step-by-step explanation:
The major conditions necessary to conduct a t-test about a mean include;
- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.
- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.
- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.
Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.
It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.
Hope this Helps!!!
So first I would say, what if all of them were dimes, how far away would it be from $14?
So 92 coins * 10 cents = $9.20
So it's 4.80 dollars away from 14 dollars.
So if we were to switch one to a quarter, it would increase by 0.15 cents.
So we want to see how many increases we need to reach 4.80 dollars more.
4.80/0.15 = 32
So there are 32 quarters and 60 dimes.
MP
PM
Assuming your n is on a side
The most likely number of bags of peanuts she
sold is 20 bags of peanut at at $4 each
<h3>Equation</h3>
Kiyo:
94 = 10 + x
94 - 10 = x
84 = x
Aleja
94 = 14 + y
94 - 14 = y
80 = y
- Find the highest common factor of 84 and 80
80 = 1, 2, 4, 5, 8, 10, 16, 20, 40 and 80.
84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84
- The highest common factor is 4
80 ÷ 4 = 20 bags of peanut
84 ÷ 4 = 21 bags of peanut
Learn more about equation:
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25 because Becky read 45 and Jason read 20
45-20 = 25
