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seraphim [82]
1 year ago
13

Hi I'm the mom I would like to see if you can help me with this problem

Mathematics
1 answer:
Tanya [424]1 year ago
5 0

From the statement of the problem, we know that:

• a train starts at City A and travels 2,158 km to City B,

,

• then it travels 3,793 km from City B to City C.

The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.

Looking at the answer of Clay:

<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>

We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.

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-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




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3 years ago
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Answer:

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https://www.numerade.com/questions/reasoning-in-exercises-35-and-36-you-are-melting-a-rectangular-block-of-wax-to-make-candles-how-ma-2/

This link lets you access a video for the correct answer

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