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seraphim [82]
1 year ago
13

Hi I'm the mom I would like to see if you can help me with this problem

Mathematics
1 answer:
Tanya [424]1 year ago
5 0

From the statement of the problem, we know that:

• a train starts at City A and travels 2,158 km to City B,

,

• then it travels 3,793 km from City B to City C.

The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.

Looking at the answer of Clay:

<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>

We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.

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Effectus [21]
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3 years ago
Need help fast please! Factor by grouping. 6x³ + 24x² -7x -28 =
olchik [2.2K]

Answer:

(x+4)(6x^2 - 7)

Step-by-step explanation:

Focus on the first 2 terms first and on the second 2 terms last:

6x^3 + 24x^2 = 6x^2(x+4)

-7x-28 = -7(x+4)

We see that the factor (x+4) is common to both pairs:  common to the first 2 terms and common to the last 2 terms.

Thus,

6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)

Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).

5 0
3 years ago
The probability of the number of defective circuit boards in a shipment is given in the tables for two different companies. Comp
Evgen [1.6K]

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qaws [65]

Answer:

f^{-1}(x)=\sqrt[3]{x}-6

Step-by-step explanation:

f(x)=(x+6)^3

y=(x+6)^3

x=(y+6)^3

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\sqrt[3]{x}-6=y

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2 years ago
Please help, I’ve been stuck on this question for about a hour now.
Hoochie [10]
6x + 5x + (x + 16) + (3x - 1) = 360
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x = 23


6(23) = 138
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(3(23) - 1) =68
5(23) = 115

138 + 39 + 68 + 115 = 360
7 0
3 years ago
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