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BartSMP [9]
4 years ago
15

8j^3 + 4j^2 + 10j + 5 factor this expression with work?

Mathematics
2 answers:
kvv77 [185]4 years ago
7 0

Factor 8j^3+4j^2+10j+5

(2j+1)(4j^2+5)


I hope that's help !

nevsk [136]4 years ago
3 0
First group the like terms:
8j^3+4j^2+10j+5
Set a common factor for two terms:
4j^2(2j+1)+5(2j+1)
Since it is like adding numbers with common factors.

(4j^2+5)(2j+1)

Hope this helps :)
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The degrees of freedom for the numerator on this case is given by df_{num}=k-1=4-1=3 where k =4 represent the number of groups.

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