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2 years ago

Making an inference is the second part of the process of investigating a

Mathematics

1 answer:

Mademuasel [1]2 years ago

5 0

Answer:

The answer is False

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5 x 3 x 2 +3/0 -45/3+1 =

Norma-Jean [14]

$5 \times 3 \times 2 + \frac{3}{0} - \frac{45}{3} + 1 = \\ \\ = \frac{3}{0} \\ \\ or \\ \\ 1. \: 30 + \frac{3}{0} - \frac{45}{3} + 1 \\ 2. \: 30 + \infty - \frac{45}{3} + 1 \\ 3. \: 30 + \infty - 15 + 1 \\ 4. \: \infty$

Yeah it's Impossible

4 0

3 years ago

Read 2 more answers

Find the approximate circumference of a circle with a diameter of 100 yards.

elixir [45]

Answer:

D. 314 yds

Step-by-step explanation:

Given:

Diameter = 100 yds

Required;

Circumference of the circle

Solution:

Circumference of circle = πd

Plug in the value

Circumference = π × 100

= 314 yds (nearest whole number)

5 0

3 years ago

Subtract 6 from me. Then multiply by 2. If you subtract 40 and then divide by 4, you get 8. What number am I?

aliina [53]

Answer:

Step-by-step explanation:

Let the number be "x"

We translate the word equation to algebraic equation.

First,

subtract 6 from me, so we have:

x - 6

Now,

Multiply by 2, so we have:

2(x-6)

Now,

Subtract 40, then divide by 4:

$\frac{2(x-6)-40}{4}$

Now, you get "8", so equate this to 8, we get:

$\frac{2(x-6)-40}{4}=8$

We now solve using algebra:

$\frac{2(x-6)-40}{4}=8\\2(x-6)-40=4*8\\2(x-6)-40=32\\2x-12-40=32\\2x-52=32\\2x=32+52\\2x=84\\x=42$

The number is 42

7 0

3 years ago

A new shoe comes in two colors,black or red,and in sizes 5 to 12,including half sizes.If a pair of the shoes is chosen at random

Dima020 [189]

Less then 50% thats foshow

5 0

2 years ago

Express the negations of each of these statements so that all negation symbols immediately precede predicates. a) ∀x∃y∀zT(x, y,

Gnesinka [82]

Answer:

a) ∀x∃y ¬∀zT(x, y, z)

∀x∃y ∃z ¬T(x, y, z)

b) ∀x¬[∃y (P(x, y) ∨ Q(x, y))]

∀x∀y ¬ [P(x, y) ∨ Q(x, y)]

∀x∀y [¬P(x, y) ^ ¬Q(x, y)]

c) ∀x ¬∃y (P(x, y) ^ ∃zR(x, y, z))

∀x ∀y ¬(P(x, y) ^ ∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ¬∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ∀z¬R(x, y, z))

d) ∀x¬∃y (P(x, y) → Q(x, y))

∀x∀y ¬(P(x, y) → Q(x, y))

∀x∀y (¬P(x, y) ^ Q(x, y))

3 0

2 years ago

Read 2 more answers