Making an inference is the second part of the process of investigating a

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter

Digiron [165]

Answer:

at least 5

Step-by-step explanation:

If the question was similar to the one given below

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?

The answer would be as follows

If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

4C2= 6 ways to use these letters and the comma

If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

5C2= 10 ways to use these letters and the comma

If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

6C2= 15 ways to use these letters and the comma

We need the least number of the alphabets to assign codes to 12 participants.

So the least number of alphabets is 5 because it can give codes to at least to 12 people .

Pair of alphabets + distinct letter ≥ 12

5 + 1 ≥ 12

6c2 ≥ 12

15 ≥ 12

3 0

2 years ago

Find the solutions to the equation below 30x^2-28x+6 =0

Naddik [55]

For this case, we have the following equation of the second degree:

$30x ^ 2-28x + 6 = 0$

If we divide between 2 on both sides of the equation, we will have:

$15x ^ 2-14x + 3 = 0$

Where:

$a = 15\\b = -14\\c = 3$

The solutions will come from:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Substituting:

$x = \frac {- (- 14) \pm \sqrt {(- 14) ^ 2-4 (15) (3)}} {2 (15)}\\x = \frac {14 \pm \sqrt {196-180}} {30}\\x = \frac {14 \pm \sqrt {16}} {30}\\x = \frac {14 \pm4} {30}$