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Vanyuwa [196]
2 years ago
5

Making an inference is the second part of the process of investigating a

Mathematics
1 answer:
Mademuasel [1]2 years ago
5 0

Answer:

The answer is False

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Need help as soon as possible​
choli [55]

Answer:

Sin(F)  = 12/13

Cos(F)  = 5/13

Tan(F) = 12/5

Step-by-step explanation:

Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.

So

Sin(F) = Opp./Hypo = 12/13

Cos(F) = Adj./Hypo = 5/13

Tan(F) = Opp./Adj. = 12/5

7 0
3 years ago
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Use the Normal model N(1156,59) for the weights of steers.
madam [21]
What weight represents 39th percentile
5 0
3 years ago
The sum of two numbers it 226. their differences is 200. what are the numbers?
jekas [21]
<span>To get the bigger number, divide by 2 the sum of the given sum of the numbers and their difference. In this case-
(226 + 200)/2 = 426/2 = 213.
To get the smaller number, divide by 2 the difference of the given sum of the numbers and their difference. In this case -
(226 - 200)/2 = 26/2 =13.
The two numbers are 213 and 13.
The bigger number is 213</span>
7 0
3 years ago
Find the value of y?
mezya [45]
I believe Y=4.......
5 0
3 years ago
A rectangular box is to have a square base and a volume of 40 ft3. If the material for the base costs $0.36/ft2, the material fo
blagie [28]

Answer:

  • length: 2 ft
  • width: 2 ft
  • height: 10 ft

Step-by-step explanation:

The total cost of the top and bottom is $0.36 + 0.14 = $0.50 per square foot.

The total cost of a pair of opposite sides is $0.05 +0.05 = $0.10 per square foot.

A minimum-cost box will have the cost of any pair of opposite sides be the same. Here, that means the box will have a side area that is 5 times the area of the top or bottom.

Since the base is square, that means the box is the shape of 5 cubes stacked one on the other. Each of those would be 8 ft³, so would have edge dimensions of ∛8 = 2 feet. The height is 5 times that, or 10 ft.

The box is 2 feet square by 10 feet high:

  • length: 2 ft
  • width: 2 ft
  • height: 10 ft

_____

If you feel the need to write an equation, you can let x represent the edge length of the base. Then the cost of the top and bottom will be ...

  top&bottom cost = 0.50·x²

The height of the box is 40/x², so the cost of the four sides will be ...

  side cost = (0.05)(4x)(40/x²) = 8/x

This is minimized when the derivative of the sum of these costs is zero:

  cost = top&bottom cost + side cost

  cost = 0.50x² + 8/x

  d(cost)/dx = 1.00x -8/x² = 0

Multiplying by x², we get ...

  x³ -8 = 0

  x = ∛8 = 2 . . . . . . as above

  height = 40/x² = 40/4 = 10 . . . . . as above

6 0
3 years ago
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