Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
boi its 202 -1
Step-by-step explanation:
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Answer:
35
Step-by-step explanation:
if you order the numbers from least to greatest, there are 14 numbers (which is even which means their is going to be two median. when you have two medians you add them and then divide them by 2) 35 + 35 = 70, 70 divided by 2 is 35. the answer is 35!
The answer is 4.5 miles. Hope it helps!
L = 4d + 54
after crew worked 33 days...d = 33
L = 4(33) + 54
L = 132 + 54
L = 186...so after 33 days, the crew made a road that measures 186 miles
