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3 years ago

Estimate 4704 - 1193 by first rounding each number to the nearest hundred.

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

$3500$

Step-by-step explanation:

Given the following question:

$4704-1193$

To estimate we to the nearest hundred we have to look at the number next to the hundreds place value to determine if it's greater than five.

$4704$

$0 < 5 = 4700$

$1193$

$9 > 5 = 1200$

$4700 - 1200$

$4700 -1200=3500$

$=3500$

Hope this helps.

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Schach [20]

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Step-by-step explanation:

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Scale factor:

1:2

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3 years ago

Is this correct not that sure

Arte-miy333 [17]

Yes there is a 2/3 chance. This is fun stuff!

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3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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3 years ago

which rate can you set 7 miles over 1 hour equal to in order to find the distance traveled in 49 hours at 7 miles per hour

IrinaVladis [17]

Answer:

Step-by-step explanation:

time = 49 hours

speed = 7 miles/hour

speed = distance / time

∴ distance = speed × time

= 7 × 49

= 343 miles

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3 years ago

A toy store had 594 games.<br> It sold 62 of these games.<br> How many games are at the store now?

Alex73 [517]

Answer: 532 games

Step-by-step explanation:

Subtract 62 from 594

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3 years ago