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Natasha_Volkova [10]
3 years ago
11

A small can contain 2 cups of soup. do 3 small cans have a greater amount than a 1 - quart container of soup.

Mathematics
2 answers:
Elza [17]3 years ago
8 0

Answer:

quarts. 11. fluid ounces = —. 1. 4. — quart. 12. quarts = 6 gallons. 13. 16 pints = gallons. 14. ... How many times must a 1-cup measuring cup be filled to equal 4 pints? 2. Leroy has 2 containers. ... can hold. Write cup, pint, quart, or gallon. 15. a bathtub. 16. a container of orange juice. 17. a juice box. 18. a small milk carton. 1

Step-by-step explanation:

Alexeev081 [22]3 years ago
3 0

Answer:

Yes, 3 small cans has a greater amount that 1 quart.

Step-by-step explanation:

1 quart only has 4 cups. 3 small cans has 6 cups.

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xxMikexx [17]

Answer:

I think the answer is about 10

Step-by-step explanation:

6 0
3 years ago
Which figures can the composite figure be broken into? A. a square pyramid and a square prism B. a square pyramid and a cube C.
kifflom [539]

Answer:

c

Step-by-step explanation:

the base dimensons of the bottom portion are not the same therefore it cannot be a cube. so it is c a triangular pyramid and square prism

7 0
3 years ago
Read 2 more answers
If f(x)= x-3/x , g(x)=x+3 , and h(x)=2x+1 , what is (g*h*f)(x) ?
alexgriva [62]

Answer:

Option B is correct

Step-by-step explanation:

We need to find g(h(f(x))

We first find h(f(x))

f(x) = x-3/x

Putting value of f(x) in place of x in h(x)

h(x) = 2x+1

h(f(x)) = 2(x-3/x) + 1

         = 2(x-3/x) + 1

         = 2x -6 /x +1

         = 2x-6 +x/x

         = 3x-6/x

Now, putting value of h(f(x)) in g(x)

g(x) = x+3

g(h(f(x)))= (3x-6/x) + 3

            = 3x-6/x + 3

            = 3x-6+3x/x

            = 6x-6/x  

So, Option B is correct.

6 0
3 years ago
The class sold 5 boxes of chocolate. jay sold 5, susan sold 8 james sold 9 how many did josh sell?​
GarryVolchara [31]

Answer:

josh sold 3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

2=a(0)^2+b(0)+c

c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

substitute equation A in equation B

0=4(b-2)-2b+2

solve for b

0=4b-8-2b+2

2b=6

b=3

Find the value of a

a=3-2=1

therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

7 0
3 years ago
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