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Sever21 [200]
3 years ago
7

which points are solutions to the system of inequalities shown below? y>x+1 y>3 x<5 A.(1,5) B.(0,6) C.(5,6) D.(3,5) E.(

4,1) F.(4,4) (Multiply answers, ive tried to understand this but I just don't get it)
Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0
1^o\ y \ \textgreater \  x+1;\\2^o\ y \ \textgreater \  3;\\3^o\ x \ \textless \  5\\\\A.\ (1;\ 5)\to x=1;\ y=5\\1^o\ 5 \ \textgreater \  1+1\to 5 \ \textgreater \  2\ OK\\2^o\ 5 \ \textgreater \  3\ OK\\3^o\ 1 \ \textless \  5\ OK\\\boxed{:)}\\B.\ (0;\ 6)\to x=0;\ y=6\\1^o\ 6 \ \textgreater \  0+1\to 6 \ \textgreater \  1\ OK\\2^o\ 6 \ \textgreater \  3\ OK\\3^o\ 0 \ \textless \  5\ OK\\\boxed{:)}
C.\ (5;\ 6)\to x=5;\ y=6\\1^o\ 6 \ \textgreater \  5+1\to 6 \ \textgreater \  6\ :(\\\\D.\ (3;\ 5)\to x=3;\ y=5\\1^o\ 5 \ \textgreater \  3+1\to 5 \ \textgreater \  4\ OK\\2^o\ 5 \ \textgreater \  3\ OK\\3^o\ 3 \ \textless \  5\ OK\\\boxed{:)}
E.\ (4;\ 1)\to x=4;\ y=1\\1^o\ 1 \ \textgreater \  4+1\to 1 \ \textgreater \  5 :(\\\\F.\ (4;\ 4)\to x=4;\ y=4\\1^o\ 4 \ \textgreater \  4+1\to 4 \ \textgreater \  5\ :(

Your\ answer:\\\boxed{A;\ B;\ D}
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How do I figure this problem 1/5 &gt; d + 4/5
marissa [1.9K]
\frac{1}{5}>d+\frac{4}{5}\ \ \ \ \ \ \ \ |subtract\ \frac{4}{5}\\\\\frac{1}{5}-\frac{4}{5}>d\\\\d
7 0
3 years ago
Find the number of possible outcomes in the sample space. The chess club must decide when and where to meet for a practice. The
Lesechka [4]

Solution

- The number of possible outcomes in the sample space is simply gotten by multiplying out all the events together.

- There are 3 possible days: Tuesday, Wednesday, or Thursday. Thus, there are 3 possible outcomes.

- There are 3 possible times: 3PM, 4PM, or 5PM. Thus, there are 3 possible outcomes again.

- There are also 9 possible classrooms available meaning another 9 possible outcomes.

- Thus, the total possible outcomes in the sample space is

3\times3\times9=81\text{ possible outcomes}

4 0
1 year ago
How do I simplify a fraction? For example if the question is 7 1/5 divided by 2 2/15 what would I do to simplify?
Westkost [7]
7 1/5:
Multiply the denominator and the whole number: 7*5 = 35 and then add the numerator: 35+1= 36/5. Then, do this for the following fraction, the improper fraction value of 2 2/15 is 32/15.
Now we need 36/5 & 32/15 to have common denominators so that we can simplify it a little less complicated.

For Instance,

36/5*3= 108/15

Now we divide, (108/15)/(32/15)
108/32= 3.375 = 3 3/8

Answer is 3 3/8.

Hope this was easy to understand!
3 0
3 years ago
Simplify 3x³(x+2)+2x(x²+3x)​
max2010maxim [7]

Answer:

{3x}^{4} +  {8x}^{3}   +  {6x}^{2}

Step-by-step explanation:

{3x}^{3} (x + 2) + 2x( {x}^{2}  + 3x)

{3x}^{4}  +  {6x}^{3}  +  {2x}^{3}  +  {6x}^{2}

{3x}^{4} +  {8x}^{3}   +  {6x}^{2}

<h3>Hope it is helpful...</h3>
8 0
3 years ago
Someone, please help me with this asap! And no links or weird answers, please!
kupik [55]

Answer:

b = 4

Step-by-step explanation:

subtract by 5 on both sides. ur left with

{b}^{2}  = 16

square root b and 16. the square root cancels out b squared. find the square root of 16. the square root of 16 is 4

3 0
2 years ago
Read 2 more answers
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