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Ludmilka [50]
3 years ago
15

What is 60/42 in simplest form

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
4 0
10
---
8 is the simplest form from that I could find.
Natalka [10]3 years ago
4 0
<span>60/42 = 10/7=1 3/7

Hoped I helped!</span>
You might be interested in
Triangle ABC has vertices at (-4,0) (-1,6) and (3,-1) What is the perimeter of triangle ABC rounded to the nearest tenth.
Marizza181 [45]
Here, Vertices: A(-4, 0) B(-1, 6) C(3, -1)

Length of AB = √(6 - 0)² + (-1 + 4)²
= √6² + 3²
= √45

Length of BC = √(-1-6)² + (3+1)²
= √-7² + 4²
= √65

Length of AC = √(0+ 1)² + (-4 - 3)²
= √1² + 7²
= √50

Perimeter = sum of all sides:
So, P = √45 + √65 + √50 = √160 = 4√10

In short, Your Answer would be 4√10 units

Hope this helps!

4 0
3 years ago
Read 2 more answers
Is my answer correct? if not please correct me
guapka [62]

Answer:

Yes it is

Step-by-step explanation:


5 0
3 years ago
Find the equation of the line: With an x intercept of 4 and ay intercept of −1.5.
Mekhanik [1.2K]

Answer:

y = (3/8)x - 1.5

Step-by-step explanation:

Use the slope-intercept form y = mx + b.  Substitute -1.5 for b, 4 for x and 0 for y.  Then:  0 = m(4) - 1.5, or

4m = 1.5, or

The slope is m = 1.5/4, or m = 0.375, or m = 3/8.

Note that the x-intercept can be treated just like any other point:  (4, 0)

Then the desired equation is     y = (3/8)x - 1.5

8 0
3 years ago
Read 2 more answers
This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is
BaLLatris [955]

Answer:

\frac{r}{3\pi h+r}

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}

Now, area of 2 cylinders would be the formula:

A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm  divided  by A_total.

Shown below:

\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}

We simplify further:

\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}

THis is the answer.

6 0
2 years ago
Read 2 more answers
The question is below
irina1246 [14]

Answer:

star

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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