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Step2247 [10]
3 years ago
10

Please help, due in 1 day; which is tomorrow

Mathematics
2 answers:
MrRa [10]3 years ago
6 0
Already answered in the other one.
GrogVix [38]3 years ago
5 0
1) 360°-18°-18°-3x°-3x°=0
     6x=324°
      x=54°
2) 180°-49°-(x+3)°=0
      (x+3)°=131°
      x=128°
3) 90°-42°-4x°=0
   4x°=48°
    x=12°
4) 180°-86°-2x°=0
   2x°=94°
   x=47°
5) 360°-117°-117°-3x°-3x°=0
   6x=126°
  x=21°
6) 90°-66°-8x°=0
    8x=24°
    x=3°
7) 180°-22°-(x-5)°=0
     (x-5)°=158°
     x=163°
8)  90°-2x°-2x°=0
     4x°=90°
     x=22.5° (i don't know if you can leave it like this or you have to write it in                      another way)
9) 90°-57°-3x°=0
   3x°=33°
   x=11°
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A storage container is rectangular and has a length of 15ft and a width of 4ft. It will hold 270 cubic feet of materials. What i
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3 0
3 years ago
Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb
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Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

\frac{2.50x}{2.50} Dividing each sides by 2.50.

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Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

8 0
3 years ago
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