Hello,
5x²+5y²-20x+30y+40=0
==>x²+y²-4x+6y+8=0 (divided by 5)
==>(x²-2*2x+4)+(y²+2*3y+9)+8-4-9=0
==>(x-2)²+(y+3)²=5
Center (2,-3)
Radius= √5≈2.2360...
We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
The answer is 76 and 76 and 28 and 124. All angles of a triangle adds up to 180 degrees. Two angles of an isosceles triangle are congruent or equal to one another.
I will help but can u like not zoom in so
Much...
Answer:
AO and OC
x+8 and 16-x
x+8 = 16-x
x+x= 16-8
2x= 8
x= 8/2
x=4
DO and OB
2y+13 and 5y+4
2y+13 = 5y+4
2y-5y= 4-13
-3y = -9
y= 9/3
y= 3
Step-by-step explanation:
i hope this helps
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