Answer:
Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Step-by-step explanation:
- State the null and alternative hypothesis as
H0: μ= 160 against the claim Ha :μ ≠160
Sample mean = x`= 165
Sample standard deviation= Sd= 12
2. The test statistic to use is
t= x`-μ/sd/√n
which if H0 is true , has t distribution with n-1 = 36-1= 35 degrees of freedom
3. The critical region is t< t (0.025(35)= 2.0306
t= x`-μ/sd/√n
4. t = (165-160)/[12/√(36)] = 5/[6] = 0.833
5. Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Now
6. The p-value is 0 .410326 for t= 0.8333 with 35 degrees of freedom.
Answer:
x= 6
Step-by-step explanation:

You will subtract 10x from 12x and get 2x

Subtract 4 from 16 to get 12

You will then divide both sides by 2
= 
x= 6
The second one is hard to read but since ∠3 is 54° you should just start from there
Hope this helps
Answer:
is it me or can I not see anything
Answer:9
Step-by-step explanation: x+4=13
x=13-4
x=9
Answer:
10 i think
Step-by-step explanation: