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Aneli [31]
3 years ago
12

How many gallons of a 30% salt solution must be added to 40 gallons of a 12% salt solution to obtain a 20% solution?

Mathematics
1 answer:
Sati [7]3 years ago
7 0
Let’s call the number of gallons of 30% solution “x”. If we mix together 40 gallons and x gallons of solution, we’re going to come out with a total of 40 + x gallons of that 20% solution. Mathematically, this is

40(12%) + x(30%) = (40 + x)(20%)

With the percents as decimals:

40(0.12) + x(0.3) = (40 + x)(0.2)

Simplifying, we have:

4.8 + 0.3x = 8 + 0.2x

Collecting the x terms on one side and the constants on the other:

0.1x = 3.2

And multiplying both sides by 10 to find x:

x = 32

So, you’ll need 32 gallons of 30% solution to yield 40 + 32 = 72 gallons of 20% solution.
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