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Aneli [31]
3 years ago
12

How many gallons of a 30% salt solution must be added to 40 gallons of a 12% salt solution to obtain a 20% solution?

Mathematics
1 answer:
Sati [7]3 years ago
7 0
Let’s call the number of gallons of 30% solution “x”. If we mix together 40 gallons and x gallons of solution, we’re going to come out with a total of 40 + x gallons of that 20% solution. Mathematically, this is

40(12%) + x(30%) = (40 + x)(20%)

With the percents as decimals:

40(0.12) + x(0.3) = (40 + x)(0.2)

Simplifying, we have:

4.8 + 0.3x = 8 + 0.2x

Collecting the x terms on one side and the constants on the other:

0.1x = 3.2

And multiplying both sides by 10 to find x:

x = 32

So, you’ll need 32 gallons of 30% solution to yield 40 + 32 = 72 gallons of 20% solution.
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How many zeros should have 5 to have 72 dividers?
xenn [34]
Hello,

nice as problem.

| If\ a\ number\ x=a_1^{p_1}*a_2^{p_2}*a_3^{p_3}*....*a_n^{p_n}\\ the\ number\ of\ his\ dividers is:\\{p_1+1}*{p_2+1}*{p_3+1}*....*{p_n+1}
Here x has a power of 5 as divider and a power of 2 as divider (in order to make a power of 10.

5=5^1*2^0

50=5^1*(5^1*2^1)=5^2*2^1

500=5^1*(5^2*2^2)=5^3*2^2

50 000 000=5^8*2^7

Numbers of dividers: (8+1)*(7+1)=9*8=72








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Answer:

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Step-by-step explanation:

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__

2. The y-intercept is the point corresponding to x=0. The y-value when x=0 is the constant in the equation: 10. Then the point is ...

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