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Evgesh-ka [11]
3 years ago
11

The height above the ground (in feet) of a ball dropped from the top of a 30-foot-tall building after t seconds is given by the

polynomial − 16t^2 + 30 . What is the height of the ball after 1/2 second?
Mathematics
1 answer:
finlep [7]3 years ago
4 0

The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h(t)= -16t^2+30. what is the height of the ball after 1/2 second?

h(t)= -16t^2+30

--

Sub 1/2 for t to find h(1/2)

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