The factorization if the given expression 128 + 2d³ is 2(64 + d³).
<h3>Factorization</h3>
128 + 2d³
There are two parameters in the expression;
The common factors between 128 and 2d³ is 2
So,
128 + 2d³
= 2(64 + d³)
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Answer:
6ab + b^2 - 17a - 4b + 10
Step-by-step explanation:
-2(a+b-5)+3(-5a+2b)+b(6a+b-8)
Now we break the parenthesis. To break that, we multiply each of the value inside the parenthesis by the adjacent number. That is, for the first part of the expression, we multiply by -2, then by 3, and then by b.
Algebraic Operations need to be considered:
[ (-) x (-) = (+); (-) x (+) = (-)]
= [-(2*a) + (-2*b) - (-2*5)] + [3*(-5a) + (3*2b)] + [(b*6a) + (b*b) - (b*8)]
= -2a - 2b +10 -15a + 6b + 6ab + b^2 - 8b
Now, we will make the adjustment by the similarity value.
= - 2a - 15a - 2b + 6b - 8b + 6ab + b^2 + 10
= - 17a - 4b + 6ab + b^2 + 10
= 6ab + b^2 - 17a - 4b + 10
Therefore, the answer of the expression is = 6ab + b^2 - 17a - 4b + 10
Answer:
4180 AED
Step-by-step explanation:
Given data
Principal= 4000
Time= 3 years
Rate= 1.5%
The compound interest expression is given as
A= P(1+r)^t
substitute
A=4000(1+0.015)^3
A= 4000(1.015)^3
A= 4000*1.045
A= 4180
Hence the worth will be 4180 AED
Y = -6.
-2(7)-2y=-2
-14-2y=-2
you need to move -14 to the other side by canceling out -14 with +14, and add +14 to -2, giving you -2y=12. -2/12=-6
(a) need to find the number of books, we'll call it "b". then the money (6w) minus the cost of books (17b) equals change left over (w)
6w - 17b = w
6w - w = 17b
5w = 17b
(5/17)w = b
(b) if w = 34
(5/17) *34 = b
10 = b
