Find the sum of the first 44 terms of the following series, to the nearest integer. 10, 14,18,...
1 answer:
Answer:
4224
Step-by-step explanation:
Here, we want to calculate the sum of the first 44 digits
Term a which is first digit is 10
common difference which is difference of terms = 14-10 = 18-14 = 4
Now the nth term of an arithmetic sequence is
a + (n-1)d
44th term means n = 44
10 + (44-1)4
10 + 43(4)
10 + 172 = 182
To find the sum, we use the formula
Sn = n/2[a + L]
where a is the first term and L is the 44th term
Sn = 44/2 (10 + 182)
Sn = 22(192)
Sn = 4,224
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The answer would be C.
If you do -5.5 + 2.5 over 6.1 - 3.1 it would be -3 over 3 which is equal to -1.
You could also do -2.5 + 5.5 over 3.1 - 6.1. It would be 3 over -3 which is also equal to -1.
X= 3 and x= -3 that should be the correct answer
Domain = R
Range = R .............
Answer:
Step-by-step explanation:
Let x be the brother's weight.
Then 2x-5 is Andy's weight.
x+(2x-5)=100
3x-5=100
3x=105
-.5 , -1.75, 3 hope that's what you wanted<span />
