Answer:
Tina will pay $12.95 for shipping and handling.
Step-by-step explanation:
Because you literally just have to multiply $62.95 by .2 and you have your answer.
The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
Let x = length of base and leg
The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base
P = b₁ + b₂ + 2(leg)
28 = 3x + 5x + 2(x)
28 = 8x + 2x
28/10 = 10x/10
2.8 = x
Now, substitute the values:
P = b₁ + b₂ + 2(leg)
28 = 3(2.8) + 5(2.8) + 2(2.8)
28 = 8.4 + 14 + 5.6
28 = 28
Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
The answer to 4-6 is negative 2
Answer:
1.89
Solution:
We have -44x - 86 = -3
First, we move the non x terms to the RHS of the equation. To do this, we add 86 to both sides.
Note: if a = b, then a + c = b + c
Therefore, -44x - 86 + 86 = -3 + 86
or, -44x = 83
Next, divide both sides by -44, which is the coefficent of x
Note: if a = b, then a ÷ c = b ÷ c
-44x
-44
=
83
-44
or, x = -1.89
Explaination:
This is right I guess
AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
