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3 years ago

Instructions:Select the correct answer.

1 answer:

8 0

Activity series of metals: K,Na,Mg,Al,Zn,Fe,Cu,Ag. Metals on the left are more reactive than metals on the right. For example Zn is more reactive than Fe and can displace him.
Reaction than can occur is: CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s).

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Mengapa dinding kapilari darah berbeza berbanding dinding vena dan arteri

olga55 [171]

Answer:

Kapilari lebih kecil dan paling banyak saluran darah, mereka membentuk sambungan antara vesel yang membawa darah dari pendengaran (arteri) dan vesel yang mengembalikan darah ke jantung (urat)

Fungsi utama kapilari ialah pertukaran bahan antara sel darah dan tisu.

Veins membawa darah ke arah jantung; selepas ia melewati kapilari dan masuk melalui urat terkecil (venules).

Arteri membawa darah dari jantung; arteri sistemik mengangkut darah oksigen dari ventrikel kiri ke tisu badan.

Explanation:

(translated version)

Why blood capillary walls differ from veins and arteries

Capillaries are smaller and the most numerous of the blood vessels, they form the connection between the vessels that carry blood away from the hear (arteries) and the vessels that return the blood to the heart (veins)

The primary function of the capillaries is the exchange of materials between the blood and tissue cells.

Veins carries the blood towards the heart; after it passes through the capillaries and enters through the smallest veins (venules).

Arteries carries blood away from the heart; systemic arteries transport oxygenated blood from the left ventricle to the body tissues.

5 0

3 years ago

In terms of bonds, what would the molecule C₆H₁₂ be classified as?

Colt1911 [192]

Answer:

Alkene

Explanation:

5 0

3 years ago

How many moles of N2 in 57.1 g of N2?

SpyIntel [72]

We are given –

Mass of $\bf N_2$ is 57.1 g and we are asked to find number of moles present in 57.1 g of $\bf N_2$

$\qquad$ $\pink{\bf\longrightarrow { Molar \:mass \:of \: N_2:-} }$

$\qquad$ $\bf \twoheadrightarrow 14\times 2$

$\qquad$ $\bf \twoheadrightarrow 28$

$\qquad$ ____________________

Now,Let's calculate the number of moles present in 57.1 g of $\bf N_2$

$\qquad$ $\purple{\bf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}$

$\qquad$ $\bf \twoheadrightarrow \dfrac{57.1}{28}$

$\qquad$ $\bf \twoheadrightarrow 2.04\: moles$

__________________________________

7 0

2 years ago

For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of

torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For $Al_2O_3$

Mass of $Al_2O_3$ = 4.07 g

Molar mass of $Al_2O_3$ = 101.96 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{4.07\ g}{101.96\ g/mol}$

$Moles\ of\ Al_2O_3= 0.0399\ mol$

According to the reaction:

$Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O$

1 mole of $Al_2O_3$ on reaction produces 1 mole of $Al_2(SO_4)_3$

So,

0.0399 mole of $Al_2O_3$ on reaction produces 0.0399 mole of $Al_2(SO_4)_3$

Moles of $Al_2(SO_4)_3$ obtained = 0.0399 mole

Molar mass of $Al_2(SO_4)_3$ = 342.2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0399= \frac{Mass}{342.2\ g/mol}$

$Mass= 13.7\ g$

Theoretical yield = 13.7 g

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

$\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100$

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

$\%\ yield =\frac{10.4}{13.7}\times 100$

% yield =76 %

6 0

3 years ago

Please help~~ thank you so much

deff fn [24]

Answer:

c. 2 and 3

Explanation:

Ca(NO3)2 names calcium nitrate.

Ca metal, O, N - nonmetals, so Ca(NO3)2 is ionic compound.

It is solid and white.

4 0

3 years ago