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IgorC [24]
3 years ago
8

What is the charge of Cl3 in PCl3​

Chemistry
1 answer:
irinina [24]3 years ago
5 0
Are subatomic particles that are manifested by forces of attraction and repulsion between them through electromagnetisms

-good luck
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How much CaCl2, in grams, is needed to make 2.0 L of a 3.5M solution?
Anvisha [2.4K]
Find the number of moles: 2•3.5=7 moles

and do dimensional analysis. to convert moles of solution to moles of cacl2 and moles of cacl2 to grams of cacl2 (molar mass)
4 0
4 years ago
Thich of the following is a chemical property2
Dimas [21]

Answer:

"Freezing point  and ability to react with oxygen" are chemical properties

Explanation:

The change of liquid into solid is the freezing point. The melting point is more than the freezing point in certain cases of mixtures for certain organic compounds like fats. As soon as the mixture freezes it becomes solid and which results in change in the composition from the liquid and solid in this way the it drastically reduces the freezing point. The melting point gets higher due to the pressure. This happens due to the release of heat of which results in the rise of temperature to the freezing point .Also the reaction of elements with oxygen which leads to formation of new substance is also an chemical property

4 0
4 years ago
A bird building a nest for its young is a reproductive strategy. Based on this example, what do you think the term “reproductive
Scilla [17]
A reproductive strategy is something done with the intent of preserving a family line so that life can continue.

please vote my answer branliest! Thanks.
8 0
3 years ago
Read 2 more answers
Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at
ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

4Al+3O_2\rightarrow 2Al_2O_3

From the balanced reaction we conclude that

As, 3 mole of O_2 react with 4 mole of Al

So, 0.188 moles of O_2 react with \frac{4}{3}\times 0.188=0.251 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 3 mole of O_2 react to give 2 mole of Al_2O_3

So, 0.188 moles of O_2 react to give \frac{2}{3}\times 0.188=0.125 moles of Al_2O_3

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of Al_2O_3 releases amount of heat = 1676 kJ

So, 0.125 mole of Al_2O_3 releases amount of heat = 0.125\times 1676kJ=209.5kJ

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0
3 years ago
Describe 3 everyday situations in which it would be useful to identify unknown substances and explain how you would identify the
andrew-mc [135]

The three situations can be described as

a) If we have two white powders and wish to distinguish between the two : the combinations can be sugar / salt or sugar / baking soda or salt / baking soda

all are kitchen items so we can either taste them

or in case of baking soda we can add it in water and it will produce brisk effervescence.

b) IF we have to distinguish in a given set of two transparent liquids which appear to be water (example water and vinegar)

we can identify them with the taste

we can identify them based on pH (vinegar will be acidic)

c) We have to find adulteration in a given sample of food

like adulteration in milk

for example presence of soap in milk

We can add indicator like phenolphthalein which will bring a pink colour in milk if soap is present

4 0
4 years ago
Read 2 more answers
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