Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
1) 2,1,2
2) 2,2,1,1
3)2,1,2
4)2,2,3
5)2,3,1,3
6 [ I cannot answer that]
7)6,1,2
Question: <em>What is the hybridization of each carbon and oxygen atoms in vitamin C?</em>
Answer:
1. To decide the hybridization of a carbon, look at how many atoms are attached to it (including the hydrogens that may be unwritten). If there are 4 total atoms attached (all with single bonds), the carbon must have sp3 orbitals (there are 4 of them). If 3, then sp2. If 2, then sp. Carbon can't be sp3d or sp3d2 hybridized because carbon is in the 2nd period of the periodic table and doesn't possess any d orbitals to hybridize.
2. Not sure what this question means. Did you mean to type just C-C bonds? If so, just count the number of bonds between 2 carbon atoms!
3. Use VSEPR. The bond angle is as great as possible, based on the repulsion of the valence electron pairs (both bonded and lone). This is also related to hybridization. sp3 hybrid orbitals are 109.5 degress apart, sp2 is 120, sp is 180.
4. See part 1. Determine the hybridization of both C4 and C5. The overlap of an orbital from each carbon is what forms the sigma bond.
Answer:
45 °C.
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 1125 J
Mass (M) = 250 g
Final temperature (T₂) = 55 °C
Specific heat capacity (C) = 0.45 J/gºC
Initial temperature (T₁) =?
The initial temperature of the iron can be obtained as illustrated below:
Q = MC(T₂ – T₁)
1125 = 250 × 0.45 (55 – T₁)
1125 = 112.5 (55 – T₁)
Divide both side by 112.5
1125/112.5 = 55 – T₁
10 = 55 – T₁
Collect like terms
10 – 55 = –T₁
–45 = –T₁
Multiply through by –1
45 = T₁
T₁ = 45 °C
Therefore, the initial temperature of the iron is 45 °C
Answer:
Be^2+ ion
Explanation:
Be(OH)x^y- ions and Be(OH)2 solid
