Answer:
9x^2 + x + 44 and 6xy + 5y^2 + 30
Step-by-step explanation:
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((((2•(x2))+30)+(3•(x2)))+22x2)+14)+x
Step 2 :
Equation at the end of step 2 :
(((((2•(x2))+30)+3x2)+22x2)+14)+x
Step 3 :
Equation at the end of step 3 :
((((2x2 + 30) + 3x2) + 22x2) + 14) + x
Step 4 :
Trying to factor by splitting the middle term
4.1 Factoring 9x2+x+44
The first term is, 9x2 its coefficient is 9 .
The middle term is, +x its coefficient is 1 .
The last term, "the constant", is +44
Step-1 : Multiply the coefficient of the first term by the constant 9 • 44 = 396
Step-2 : Find two factors of 396 whose sum equals the coefficient of the middle term, which is 1 .
-396
+
-1
=
-397
-198
+
-2
=
-200
-132
+
-3
=
-135
-99
+
-4
=
-103
-66
+
-6
=
-72
-44 +
-9 = -53
For tidiness, printing of 30 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
9x2 + x + 44
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((5xy + 20) + 22y2) + 10) + y2) + xy
Step 2 :
Trying to factor a multi variable polynomial :
2.1 Factoring 6xy + 5y2 + 30
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Final result :
6xy + 5y2 + 30
