3 years ago

Sketch the graph of a function f for which f(0)=0,f'(0)=3,f'(1)=0, and f'(2)= -1

1 answer:

8 0

I think you have to sketch the graph

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Misha Larkins [42]

Answer:

Area of Rectangle = $26x - 2x^3$

Step-by-step explanation:

Rectangle two vertices lie on x axis ; two vertices lie on parabola $y = 13 - x^2$ .

Supposing coordinates of upper right vertex of rectangle are P = $x , y$

Due to parabola symmetry, width of rectangle is twice the distance horizontal (X) axis distance between Y axis & point P.

Width of rectangle = $2x$

Length of rectangle = $y$ ; $y = 13 - x^2$

Area of Rectangle = Length x Width

= $2x (y)$

= $2x (13 - x^2)$

= $26x - 2x^3$

5 0

3 years ago

vazorg [7]

80 divided by 2.5 is 32, if this is the entire question.

4 0

3 years ago

posledela

I think its 149/ 490. Not sure, but pretty confident. Hope this helps.

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3 years ago

spin [16.1K]

A box and whisker plot

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3 years ago

Nadusha1986 [10]

Answer:

note:

solution is attached

3 0

3 years ago