3 years ago

A car brought for 13000 deprecitates at 15 percent per year find value of car after 5 years

Mathematics

1 answer:

Nesterboy [21]3 years ago

4 0

the value of the car will be 3250 after 5 years

Step-by-step explanation:

the value of the car = 13000

rate of interest = 15%

time = 5 years

in 5 years the car will depreciates = 13000 X 15% X 5

= $\frac{13000 X 15 X 5}{100}$

= 9750

after 5 years the value of the car is = 13000 - 9750 = 3250

You might be interested in

Which statement is correct?

Elan Coil [88]

Answer:

hbw ygav

Step-by-step explanation:

7 0

3 years ago

invent three meaningful algebatric expressions of your own from the list of variables and enter them into the table below.write

Mars2501 [29]

Answer:

Step-by-step explanation:

4 0

2 years ago

Power functions mastery test

DaniilM [7]

This isn’t a question this is just a statement

7 0

2 years ago

Read 2 more answers

What is 64 mi/hr=? Ft/s please work out so I can see a example

Arlecino [84]

$64\ \frac{mile}{hour}=x\frac{feet}{second}\\\\
Converting\ unites:\\
1\ mile= 5280\ feet\\
1\ hour=\ 3600\ second\\\\
64\frac{mile}{hour}=64*\frac{5280feet}{3600second}=\frac{33792\ feet}{3600\ second}=93,9\frac{feet}{second}$

6 0

3 years ago

What is the rate of change from x = n to x = 2n?

puteri [66]

Answer:

$\dfrac{-8}{\pi}$

Step-by-step explanation:

The rate of change of the function f(x) from point $x_1$ to point $x_2$ can be calculated using formula

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

Given

$x_1=\pi\\ \\x_2=2\pi$

From the graph of the function

$f(x_1)=f(\pi)=4\\ \\f(x_2)=f(2\pi)=-4$

So, the rate of change is

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}=\dfrac{-4-4}{2\pi -\pi}=\dfrac{-8}{\pi}$

5 0

3 years ago