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2 years ago

Which angles form a linear pair? AnglePRL and AngleLRM AngleORP and AngleMRN AngleMRN and AngleNRO AngleLRP and AngleORP

Mathematics

1 answer:

Andrew [12]2 years ago

4 0

Answer: C (AngleMRN and AngleNRO)

Step-by-step explanation:

A linear pair of angles is formed when two lines intersect. Two angles are linear if they are adjacent angles (angles next to each other) formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

AngleMRN and AngleNRO together is 180 degrees

I'm not very good at explaining but hope this helps ! :)

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Lina20 [59]

Answer:

$\textbf{The slope of the parallel line is given by $ 2 $}\\$

Step-by-step explanation:

$\textup{The slope of any two parallel lines are equal and they only differ in their $y- intercepts$. }\\\textup{Given $y = 2x + 4 $}\\\textup{This is comparable to $y = mx + c$, where $m$ is the slope of that line.}\\\textup{Therefore, the slope of the given line and any line parallel to it is $ 2$.}$

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2 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

Problem ID: PRABEAF4

HACTEHA [7]

What is the question?

6 0

2 years ago

A rug is shaped like a parallelogram with a base of 41⁄2 ft. and a height of 2 1⁄4 ft. What is the area of the rug? Draw and lab

Bess [88]

Answer:

46.125 square feet or $46\dfrac{1}{8}$ sq. feet.

Step-by-step explanation:

The rug is shaped like a parallelogram with a base of $\frac{41}{2} = 20.5$ feet. and a height of $2\dfrac{1}{4} = 2.25$ feet.

Now, the area of a parallelogram is given by the product of one side as the base and the perpendicular distance of that side from the opposite parallel side as height.

Now, the area of the given parallelogram is (20.5 × 2.25) = 46.125 square feet. (Answer)

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3 years ago

your state charges 10 % of gas tax gas.cpst 2.50 per gallon if you get 6 gallons how.much will your total be

Lady_Fox [76]

the price at the end of it will be $16.5.

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3 years ago

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