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NARA [144]
2 years ago
10

What is the slope of a lline that contains points (-1,2) and (3,3)

Mathematics
1 answer:
Nesterboy [21]2 years ago
5 0

m =  \frac{3 - 2}{3 + 1}  \\  =  \frac{1}{4  }  \\ slope =  \frac{1}{4}
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2 years ago
Diamonds have a density of 3.5 g/cm3. How big is a diamond that has a mass of 0.10 g?
devlian [24]

Answer:x = 0.028571 cm3

Step-by-step explanation:

I the density is constant and a mass of 3.5 g takes up 1 cubic centimeter, how much volume will a mass of 0.20 g take (in cubit centimeters)?

So, let x be the volume in cubit centimeters.

   the mass is to the volume is as the mass is to the volume

        3.5g /(1 cm3)  =  0,1g / (x cm3)

Cross-multiply to get:

       3.5x = 0.1

         x = 0.1 / 3.5                (divide both sides by 3.5)

         x = 0.028571 cm3      (you probably should round this, but diamonds are expensive !)

7 0
2 years ago
Help me plzzzzzzzzzz I give u BRAINLY
weqwewe [10]

The answer is

X= 3 and Y= -4

6 0
2 years ago
Read 2 more answers
Sinx + siny=a<br> cosx + cosy=b<br> Find cos(x+y/2)
romanna [79]

Using the addition rule of the Sine function and the Cosine function, we obtain \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}.

<h3>What are the formulas for (sin x + sin y) and (cos x + cos y)?</h3>
  • The formula for the addition of two Sine functions (\sin x+\sin y) is \sin x + \sin y = 2\sin\frac{x+y}{2}\cos\frac{x-y}{2}.
  • The formula for the addition of two Cosine functions (\cos x+\cos y) is \cos x + \cos y = 2\cos\frac{x+y}{2}\cos\frac{x-y}{2}.

Given that

\sin x + \sin y = a\\\cos x + \cos y = b

Then using the above formulas, we get:

2\sin\frac{x+y}{2}\cos\frac{x-y}{2}=a       (1)

2\cos\frac{x+y}{2}\cos\frac{x-y}{2}=b       (2)

Dividing the equation (1) by (2), we get:

\dfrac{\sin\dfrac{x+y}{2}}{\cos\frac{x-y}{2}}=\dfrac{a}{b}\\\Longrightarrow \tan\dfrac{x+y}{2}=\dfrac{a}{b}             (3)

Now, we know that  \cos\theta=\dfrac{1}{\sqrt{1+\tan^2\theta}}.

Thus, using the above formula, we get from (3):

\cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\tan^2\dfrac{x+y}{2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\dfrac{a^2}{b^2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}

Therefore, using the addition rule of the Sine function and the Cosine function, we obtain \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}.

To know more about Sine and Cosine functions, refer: brainly.com/question/27728553

#SPJ9

3 0
1 year ago
1. Multiply (x+7)(x-7)
Yakvenalex [24]
X^2+7x-7x-49
Simplified = x^2-49
7 0
3 years ago
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