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likoan [24]
3 years ago
10

Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

A

Step-by-step explanation:

NeX [460]3 years ago
6 0
So, a line parallel to <span>y - 5x = 10, will have the same slope as that equation, so what is that slope anyway?  let's solve for "y".

</span>\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}
<span>
alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.


</span>\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 3}}\quad ,&{{ 10}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies 5&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3)&#10;\\\\\\&#10;y-10=5x-15\implies y=5x-5<span>
</span>
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