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likoan [24]
3 years ago
10

Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

A

Step-by-step explanation:

NeX [460]3 years ago
6 0
So, a line parallel to <span>y - 5x = 10, will have the same slope as that equation, so what is that slope anyway?  let's solve for "y".

</span>\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}
<span>
alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.


</span>\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 3}}\quad ,&{{ 10}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies 5&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3)&#10;\\\\\\&#10;y-10=5x-15\implies y=5x-5<span>
</span>
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Step-by-step explanation:

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Which describes the cross section of a square prism that passes through vertices A, B, and C?
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Answer:

In triangle ABC one side equal 8\sqrt{2} and two sides equal 4\sqrt{13}

Step-by-step explanation:

We are given a prism whose base is square with sides 8 in and height 12 in.

If we take cross section through vertices A, B and C

We will get a cross section as triangle.

In triangle ABC, sides are AB, BC and AC

AB is diagonal of top square whose side 8 in.

AB=\sqrt{8^2+8^2}=8\sqrt{2}

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BC is face diagonal of right face.

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AC=BC≠AB

Hence, In triangle ABC one side equal 8\sqrt{2} and two side equal 4\sqrt{13}

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Step-by-step explanation:

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Write these as a product
Oxana [17]

<u>Ans</u><u>wer</u>

a)

{(2b - 5)}^{2}  - 36 =( 2b - 11)(2b  +  1)

b)

9 -  {(7 + 3a)}^{2}  =  (3a - 4)(3a + 11)

c)

( {4 - 11m)}^{2}  - 1 =( 3 - 11m )( 5 - 11m )

<u>Explanation</u>

a) The given expresion is

{(2b - 5)}^{2}  - 36

We rewrite as difference of two squares

{(2b - 5)}^{2}  - 36 = {(2b - 5)}^{2}  -  {6}^{2}

Recall that:

{x}^{2}  -  {y}^{2}  = (x + y)(x - y)

This implies that:

{(2b - 5)}^{2}  - 36 =( {(2b - 5)} -6)(2b - 5 )+ 6)

Or

{(2b - 5)}^{2}  - 36 =( 2b - 5-6)(2b - 5 + 6)

This simplifies to give:

{(2b - 5)}^{2}  - 36 =( 2b - 11)(2b  +  1)

b) The second expression is

9 -  {(7 + 3a)}^{2}

We rewrite as perfect squares yo get:

9 -  {(7 + 3a)}^{2}  =  {3}^{2} -  {(7 + 3a)}^{2}

This gives:

9 -  {(7 + 3a)}^{2}  =  ({3} -  {(7 + 3a)})({3}  +  {(7 + 3a)})

This implies that

9 -  {(7 + 3a)}^{2}  =  ({3} -  7 + 3a)({3}  + 7 + 3a)

We simplify to get:

9 -  {(7 + 3a)}^{2}  =  (3a - 4)(3a + 11)

c) The third expression is:

( {4 - 11m)}^{2}  - 1

We obtain the difference of two squares as:

( {4 - 11m)}^{2}  - 1 =( ( {4 - 11m)}  - 1 )( ( {4 - 11m)}  + 1 )

We simplify within the parenthesis to get:

( {4 - 11m)}^{2}  - 1 =( 4 - 11m  - 1 )( 4 - 11m+ 1 )

We simplify further to get;

( {4 - 11m)}^{2}  - 1 =( 3 - 11m )( 5 - 11m )

4 0
3 years ago
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