All categories

3 years ago

Solve: (2a²+5a+2)^1/2=3

Mathematics

2 answers:

Softa [21]3 years ago

4 0

Answer: a= -7/2 or a= 1

Step-by-step explanation:

Ghella [55]3 years ago

3 0

When you have an expression to the power of (1/2) that means the same thing as having a square root.

Lets call a=x

To get rid of the square root we square both sides getting:

2x^2+5x+2= 3^2

Simplifying this we get: 2x^2+5x+2=9

We can subtract 9 from both sides getting: 2x^2+5x-7

Now when we solve for this we can use the quadratic formula:

(-b +/- sqrt(b^2-4ac)) / 2a

a=2 , b=5 , c=-7

Plugging in we end up with : (-5 +/- sqrt(81)) /4

This simplifies to : (-5 +/- 9) / 4 ..... (-5+ (-9))/4 OR (-5-(-9))/4

we have x= -14/4 , 1

You might be interested in

PLEASE HELP If You Are not SURE please don't answer PLEASE show work and steps

Ivanshal [37]

63+12x<15
12x<-48 (subtract 63 from both sides)
x<-4 (divide out the 12)

8 0

3 years ago

Read 2 more answers

Which polynomial has (3x + 2) as a binomial factor?

Nuetrik [128]

Answer:

Step-by-step explanation:

If binomial (3x+2) is a factor of some polynomial, then number is this polynomial's root. Check all polynomials:

6x^3+3x^2+4x+2

8 0

3 years ago

Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)

Nataliya [291]

Answer:

The answer to your proble I'm slow intercept from is y=-2x+8

Step-by-step explanation:

4 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

You Try: True or False: (-8) + 9 = 9+ (-8) Show your work to prove your answer.

poizon [28]

Answer:

true

Step-by-step explanation:

(-8) + 9=1

9+(-8)=9-8=1

4 0

3 years ago

Read 2 more answers