Can I get help with these questions

Bianca and Meredith are sisters. Meredith's height is 23 of Bianca's height plus 32 inches. Meredith is 60 inches tall. A girl i

jarptica [38.1K]

Answer:

Bianca's height = 42 inches

Step-by-step explanation:

Let x be the Bianca height.

Given:

Meredith height = 60 inches

We need to find the Bianca height.

Solution:

From the given statement the Meredith's height is $\frac{2}{3}$ of Bianca's height plus 32 inches, so the equation is.

Meredith's height = $\frac{2}{3}(Bianca\ height)+32$

Substitute Meredith's height in above equation.

$60=\frac{2}{3}x+32$

Now we solve the above equation for x.

$\frac{2}{3}x=60-32$

$\frac{2}{3}x=28$

By cross multiplication.

$x=\frac{3\times 28}{2}$

28 divided by 2.

$x= 3\times 14$

$x=42\ in$

Therefore, the height of the Bianca is 42 inches.

7 0

2 years ago

Someone help me with this geometry homework !!!!!! 10 points!

Reil [10]

Answer: 3a = (0, 1) 3b = (2, 1) 3c = (2.5, 1) 3d = (1.6, 1)

4a = (2, 3.5) 4b = (2, 3) 4c = (2, 5.375)

<u>Step-by-step explanation:</u>

The length of AB is 6 and is horizontal (affects the x-coordinate)

$3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)$

$3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)$

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The length of AB is 5 and is vertical (affects the y-coordinate)

$4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)$