1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
choli [55]
3 years ago
4

Gerry is looking at salt under a powerful microscope and notices a crystalline structure. What can be known about the salt sampl

e that Gerry is looking at?
1. The atoms have spread out from each other.

2.The atoms are sliding past each other.

3.The atoms have no particular pattern

4.The atoms are vibrating in place
Physics
1 answer:
nirvana33 [79]3 years ago
4 0

Answer:

4.The atoms are vibrating in place

Explanation:

The answer is;  The atoms are vibrating in place

We know that, molecules in the crystal have a definite position in the crystal and are bonded to each other by electrostatic forces. However, since the molecules have some energy, they vibrate in their positions. Their energy, however, is not high enough to cause them to overcome the strong bonding (unless the crystal is heated or the atoms are irradiated).

You might be interested in
Find mass of the object
REY [17]

Answer:

I had the same question a while ago !

Explanation:

5 0
3 years ago
A pumpkin weighs 5.4 pounds what is its mass in grams?
olga nikolaevna [1]
THe answer would be 2,449.4 grams
8 0
3 years ago
Two manned satellites approaching one another at a relative speed of 0.150 m/s intend to dock. The first has a mass of 2.50 ✕ 10
Reika [66]

Answer: u_{1}=-0.075m/s and  u_{2}=0.500m/s

Explanation:

An elastic collision is one in which both the total kinetic energy of the system and the linear momentum are conserved. That is, during the collision there is no sound, heat or permanent deformations in the bodies as a result of the impact.

Now, in the case of the satellites described here, we have:

m_{1}v_{1}+m_{2}v_{2}=m_{1}u_{1}+m_{2}u_{2}   (1)  Conservation of momentum

\frac{1}{2}m_{1}v_{1}^{2} +\frac{1}{2}m_{2}v_{2}^{2} =\frac{1}{2}m_{1}u_{1}^{2} +\frac{1}{2}m_{2}u_{2}^{2}   (2)  Conservation of kinetic energy

Where:

m_{1}=2.5(10)^{3}kg is the mass of the first satellite

m_{2}=7.5(10)^{3}kg is the mass of the second satellite

v_{1}=0.150m/s is the initial velocity of the first satellite

v_{2}=0m/s is the initial velocity of the second satellite (we are told it is at rest)

u_{1} is the final relative velocity of the first satellite

u_{2} is the final relative velocity of the second satellite

Now, as we know the second satellite is at rest before the collision, equations (1) and (2) change to:

m_{1}v_{1}=m_{1}u_{1}+m_{2}u_{2}   (3)

\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}m_{1}u_{1}^{2} +\frac{1}{2}m_{2}u_{2}^{2}   (4)

Solving this system of equations we have the equations for u_{1}  and u_{2}:

u_{1}=\frac{v_{1}(m_{1}-m_{2})}{m_{1}+m_{2}}   (5)

u_{2}=\frac{2m_{1}v_{1}}{m_{1}+m_{2}}   (6)

Substituting the known values on both equations:

u_{1}=\frac{0.150m/s(2.5(10)^{3}kg-7.5(10)^{3}kg)}{2.5(10)^{3}kg+7.5(10)^{3}kg}   (7)

u_{1}=-0.075m/s   (8)   This is the final relative velocity of the first satellite

u_{2}=\frac{2(2.5(10)^{3}kg)(0.150m/s)}{2.5(10)^{3}kg+7.5(10)^{3}kg}   (9)

u_{2}=0.500m/s   (10)  his is the final relative velocity of the second satellite

7 0
4 years ago
How can you tell whether light is polarized?
never [62]
No you can not
 atleast as far as i know
7 0
4 years ago
A raindrop of mass 2.52 × 10-5 kg falls vertically at constant speed under the influence of gravity and air resistance. Model th
goldfiish [28.3K]

Answer:

0.0247212 Joules

-0.0247212 Joules

Explanation:

Potential energy

PE=mgh\\\Rightarrow PE=2.52\times 10^{-5}\times 9.81\times 100\\\Rightarrow PE=0.0247212\ Joules

a) The work done by the gravitational force is given by the potential energy that the body has at the start of the fall.

Work done is considered as positive if the force which is being applied is in the direction of motion.

Hence, the work done on the raindrop by the gravitational force is 0.0247212 Joules

b) As the drop is falling the air resistance provides an opposite force this means the sign of the work done will be negative.

So, the work done on the raindrop by air resistance is -0.0247212 Joules

5 0
3 years ago
Other questions:
  • Which of the following treatments would enhance the level of the Pfr form of phytochrome?A) exposure to far-red lightB) exposure
    7·1 answer
  • In the early 1900s Alfred Wegener noticed that some of earths continets looked like they might fit together like a jigsaw puzzle
    10·2 answers
  • Which kind of friction requires more force to overcome rolling or sliding fricton?
    8·1 answer
  • I'm looking for the answers for 4-6 and how to do them. I have some answers already but I'm very unsure of them. Thank you!
    10·1 answer
  • 2. A rock is dropped off a bridge. How fast is the rock
    9·1 answer
  • 27. (a) What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being vi
    11·1 answer
  • How are fossil fuels different from renewable energy sources?
    15·1 answer
  • Please help! i'll give brainliest.
    11·2 answers
  • Question #4
    11·1 answer
  • As the sun sets on horizon, its rays are____ by the ocean water
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!