With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees
ELECTRIC FORCE (F)
F = ![\frac{KQq}{d^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BKQq%7D%7Bd%5E%7B2%7D%20%7D)
Where K = 9 x
N
/![C^{2}](https://tex.z-dn.net/?f=C%5E%7B2%7D)
The distance between
and
can be calculated by using Pythagoras theorem.
d = ![\sqrt{33^{2} + 33^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B33%5E%7B2%7D%20%2B%2033%5E%7B2%7D%20%20%7D)
d = 46.7 cm = 0.467 m
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 1)/![0.467^{2}](https://tex.z-dn.net/?f=0.467%5E%7B2%7D)
= 2.7 x
/0.218
= 1.24 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 4)/![0.33^{2}](https://tex.z-dn.net/?f=0.33%5E%7B2%7D)
= 1.08 x
/0.1089
= 9.92 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 2)/![0.33^{2}](https://tex.z-dn.net/?f=0.33%5E%7B2%7D)
= 5.4 x
/0.1089
= 4.96 x
N
Summation of forces on Y component will be
=
-
Sin 45
= 9.92 x
- 1.24 x
Sin 45
= 9.04 x
N
Summation of forces on X component will be
=
-
Cos 45
= 4.96 x
- 1.24 x
Sin 45
= 4.08 x
N
Net Force = ![\sqrt{F_{x} ^{2} + F_{y} ^{2} } }](https://tex.z-dn.net/?f=%5Csqrt%7BF_%7Bx%7D%20%5E%7B2%7D%20%2B%20F_%7By%7D%20%5E%7B2%7D%20%20%7D%20%7D)
Net force = ![\sqrt{(4.08*10^{11}) ^{2} + (9.04*10^{11}) ^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%284.08%2A10%5E%7B11%7D%29%20%5E%7B2%7D%20%2B%20%289.04%2A10%5E%7B11%7D%29%20%5E%7B2%7D%20%20%7D)
Net force = 9.9 x
N
The direction will be
Tan ∅ =
/![F_{x}](https://tex.z-dn.net/?f=F_%7Bx%7D)
Tan ∅ = 9.04 x
/ 4.08 x ![10^{11}](https://tex.z-dn.net/?f=10%5E%7B11%7D)
Tan ∅ = 2.216
∅ =
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
No it does not . That is the answer
Answer:
The maximum current, in amperes, that a conductor can carry continuously under the conditions of abuse without exceeding its temperature rating.
Oh my lord lol I was do ready to help then I saw numbers