The bag moves to the left.
This is because of Newton's third law of motion that states:
For every action force on a body, there is an opposite and equal reaction force.
Thus pushing the bag from the right makes it move to the left.
Answer:
No. of laps of Hannah are 7 (approx).
Solution:
According to the question:
The total distance to be covered, D = 5000 m
The distance for each lap, x = 400 m
Time taken by Kara, 
Time taken by Hannah, 
Now, the speed of Kara and Hannah can be calculated respectively as:
Time taken in each lap is given by:
t = 500 s
So, Distance covered by Hannah in 't' sec is given by:
No. of laps taken by Hannah when she passes Kara:
≈ 7 laps
Answer:
Change in velocity: 88 m/s
Average velocity: 50 m/s
initial velocity: 5.9 m/s
Final velocity: 94 m/s
Initial momentum: 3.6 kg m/s
Final momentum: 58 kg m/s
Explanation:
Acceleration = change in velocity / time
9.8 m/s² = Δv / 9.0 s
Δv = 88 m/s
Work = change in energy
Fd = ΔE
(6.0 N) d = 2700 J
d = 450 m
Average velocity = distance / time
v_avg = 450 m / 9.0 s
v_avg = 50 m/s
v − v₀ = 88 m/s
½ (v + v₀) = 50 m/s
Solving the system of equations:
v + v₀ = 100 m/s
2v = 188 m/s
v = 94 m/s
v₀ = 5.9 m/s
Use Newton's second law to find the mass:
F = ma
6.0 N = m (9.8 m/s²)
m = 0.61 kg
Find the momentums:
p₀ = (0.61 kg) (5.9 m/s) = 3.6 kg m/s
p = (0.61 kg) (94 m/s) = 58 kg m/s
Answer:
Distance in pc= 20parsecs
Distance in zLY= 65.2LY
Distance in AU= 4.1×10^6AU
Explanation:
Using the formular:
d = 1/p
Where d = distance
P= parallax angle in arc of second
d= 1/0.050
d= 20 parsed
Converting to Lighy years,LY :
1 PC = 3.26LY
d= 20pc × (3.26Ly/1pc)
d= 65.2Ly
To convert to AU, 206,265 AU = 1pc
d= 20pc × (2.06×10^5AU/1pc)
d= 4.1×10^6AU
So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
