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lesya [120]
4 years ago
15

What would be the proper way to write the name for a compound with the formula nano3?

Chemistry
1 answer:
ivann1987 [24]4 years ago
8 0
Co2 is correct hope it helps
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What do you think it is? do you know? Do you even pay attention?

Well the answer would be  <span>The process is called "lithification"-- the particles of sediment are pressed together (compaction) and held together by minerals left behind when the water is forced out</span>
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Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl
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Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = V

V_2 = final volume of gas = 2V

n_1 = initial moles of gas  = 1.56 mole

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{V}{2V}=\frac{1.56mole}{n_2}

n_2=3.12mole

Now we have to calculate the mass of helium gas at doubled volume.

\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He

\text{Mass of }He=3.12mole\times 4g/mole=12.48g

Therefore, the mass of helium gas added must be 12.48 grams.

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Explanation:

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Answer:

Explanation:

Answer is B i got it right

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