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mr_godi [17]
3 years ago
15

Draw the compound that would produce 4-ethyl-3-hexanol in the presence of a nickel catalyst and hydrogen.

Chemistry
2 answers:
MatroZZZ [7]3 years ago
5 0
In organic chemistry, there are already known reaction for synthesis that have been studied and experimented by scientists. For reactions involving a Nickel catalyst in the presence of hydrogen gas, the reaction would be hydrogenation of alkene to yield an alcohol. These reaction is anti-Markovnikov, or proceeds by violating the rule of Markovnikov. His rule states that 'the rich gets richer'. This means that the heavily substituted C atom of the alkene chain would receive another substituent. Therefore, the complete reaction would be

4-ethyl-3-hexene   ------->  4-ethyl-3-hexanol

In structural formula, the reaction goes as follows as shown in the picture.

suter [353]3 years ago
4 0

The compound that produces 4-ethyl-3-hexanol in the presence of nickel and hydrogen is \boxed{{\text{4 - ethylhexan - 3 - one}}}. (Refer to the attached image)

Further Explanation:

The reduction reaction is a process in organic reactions where hydrogen atoms with or without the presence of catalyst like (Ni, Pt, and Pd.) are added to organic molecules like alcohols, phenols, aldehyde, and alkenes. It is also defined as a reaction where a less electronegative species is added to a more electronegative species.

Reduction of aldehyde or ketone compounds in the presence of nickel catalysts and hydrogen gives alcohol as the product.

A general reduction reaction is as follows:  

{\text{RCHO}}\;{\text{ + }}\;{{\text{H}}_{\text{2}}}{\text{/Ni}} \to {\text{RC}}{{\text{H}}_{\text{2}}}{\text{OH}}

In the hydrogenation reactions of aldehyde, the reduction of the carbonyl group takes place. The reaction of an aldehyde with hydrogen gas in presence of nickel catalyst leads to the formation of a primary alcohol, whereas the reaction of ketone with hydrogen gas in presence of nickel catalyst leads to the formation of a secondary alcohol.

{\text{4 - ethylhexan - 3 - one}} reacts with hydrogen gas in the presence of nickel catalyst to undergo reduction reaction to form 4-ethyl-3-hexanol. (Refer to the attached image)

Learn more:

1. Identify the reducing reagent in the following reaction: brainly.com/question/6966537

2. Identify the reducing reagent in the following reaction: brainly.com/question/9613654

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Reduction Reaction

Keywords: Reduction reaction, hydrogen, addition, 4-ethyl-3-hexanol, aldehyde, ketone, double, single, nickel, catalyst, 4-ethylhexan-3-one, hydrogenation and 4-ethyl-3-hexanol.

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Airida [17]
I think the correct answer from the choices listed above is option 3. In the reaction 2NaCl + 2H2O ? 2NaOH + Cl2 + H2, the reactants should <span>weigh the same as the products. This is to agree with the law of conservation of mass where mass in should be equal to mass out.</span>
8 0
3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
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Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
Kahdbiaddsk;wvfodas vs;oi vsd;iv sdv;sidv s;vowdbvw;dichvbwdv;iwebfwd;iwdbcv;wkfbsdliasbv;soqivbasd
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6 0
3 years ago
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6 0
3 years ago
By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an
Serggg [28]

Answer:

The Kinetic Energy is approximately 3 times decreased

Explanation:

A baseball weighs 5.13 oz.  

a)What is the kinetic energy, in joules, of this baseball when it is thrown by a major league pitcher at 95.o mi/h?  

b) By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an integer.

Kinetic Energy (KE)=0.5×mass×velocity ^ 2

Kinetic Energy (KE)=0.5×mass × velocity ^ 2

Joules = kg×m^2/s^2

1 mile = 1609.344 meters

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1 Oz = 28.34952 g = 0.02834952 kg

a) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(95 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=130.761 kg×m^2/s^2 = 130.761 Joules

b) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(54.8 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=43.51028 kg×m^2/s^2 = 43.51028 Joules

= 130.761 / 43.51028 = 3.00528,  

As such the Kinetic Energy is approximately 3 times decreased

4 0
4 years ago
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