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mr_godi [17]
3 years ago
15

Draw the compound that would produce 4-ethyl-3-hexanol in the presence of a nickel catalyst and hydrogen.

Chemistry
2 answers:
MatroZZZ [7]3 years ago
5 0
In organic chemistry, there are already known reaction for synthesis that have been studied and experimented by scientists. For reactions involving a Nickel catalyst in the presence of hydrogen gas, the reaction would be hydrogenation of alkene to yield an alcohol. These reaction is anti-Markovnikov, or proceeds by violating the rule of Markovnikov. His rule states that 'the rich gets richer'. This means that the heavily substituted C atom of the alkene chain would receive another substituent. Therefore, the complete reaction would be

4-ethyl-3-hexene   ------->  4-ethyl-3-hexanol

In structural formula, the reaction goes as follows as shown in the picture.

suter [353]3 years ago
4 0

The compound that produces 4-ethyl-3-hexanol in the presence of nickel and hydrogen is \boxed{{\text{4 - ethylhexan - 3 - one}}}. (Refer to the attached image)

Further Explanation:

The reduction reaction is a process in organic reactions where hydrogen atoms with or without the presence of catalyst like (Ni, Pt, and Pd.) are added to organic molecules like alcohols, phenols, aldehyde, and alkenes. It is also defined as a reaction where a less electronegative species is added to a more electronegative species.

Reduction of aldehyde or ketone compounds in the presence of nickel catalysts and hydrogen gives alcohol as the product.

A general reduction reaction is as follows:  

{\text{RCHO}}\;{\text{ + }}\;{{\text{H}}_{\text{2}}}{\text{/Ni}} \to {\text{RC}}{{\text{H}}_{\text{2}}}{\text{OH}}

In the hydrogenation reactions of aldehyde, the reduction of the carbonyl group takes place. The reaction of an aldehyde with hydrogen gas in presence of nickel catalyst leads to the formation of a primary alcohol, whereas the reaction of ketone with hydrogen gas in presence of nickel catalyst leads to the formation of a secondary alcohol.

{\text{4 - ethylhexan - 3 - one}} reacts with hydrogen gas in the presence of nickel catalyst to undergo reduction reaction to form 4-ethyl-3-hexanol. (Refer to the attached image)

Learn more:

1. Identify the reducing reagent in the following reaction: brainly.com/question/6966537

2. Identify the reducing reagent in the following reaction: brainly.com/question/9613654

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Reduction Reaction

Keywords: Reduction reaction, hydrogen, addition, 4-ethyl-3-hexanol, aldehyde, ketone, double, single, nickel, catalyst, 4-ethylhexan-3-one, hydrogenation and 4-ethyl-3-hexanol.

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A chemist needs 10 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%,
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Answer:

a) 1 litre of  10% solution and 7 litre of 20% solution

b) 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) 3.75 litres of 50% solution and 6.25 litres of 20% solution

Explanation:

Given:

chemist needs = 10 liters of a 25% acid solution

Concentration of three solutions that are to be mixed = 10%, 20% and 50%.

Solution:

A) Use 2 liters of the 50% solution

Let us mix this with 10% and 20% solution

They will have to equal 8 litres

Let x=20% solution

Then (8-x) =10%

So the equation becomes,

10%(8-x)+ 20%x+50%(2)=25(10)

(0.1)(8-x) +0.2x+0.50(2)= 0.25(10)

0.8-0.1x+0.2x+1.0=2.5

0.2x-0.1x=2.5-0.8-1.0

0.1x=0.7

x=\frac{0.7}{0.1}

x= 7

so, 8-x = 8 -7= 1 litre of  10% solution and 7 litre of 20% solution

B)Use as little as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+20%(10-x)=25%(10)

0.50x+0.2(10-x)=0.25(10)

0.5x+2.0-0.2x=2.5

0.3x=2.5-2.0

0.3x=0.5

x=\frac{0.5}{0.3}

x=1.67  

now (10-x)=(10-1.67)=8.33

so there will be 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) ) Use as much as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+10%(10-x)=25%(10)

0.50x+0.1(10-x)=0.25(10)

0.5x+1.0-0.1x=2.5

0.4x=2.5-1.0

0.4x=1.5

x=\frac{1.5}{0.3}

x=3.75

Now, (10-x)=(10- 3.75)=6.26

So there will be 3.75 litres of 50% solution and 6.25 litres of 20% solution

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Answer:

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Answer:

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