Explanation:
b. Bromo cyclopentane + HBr
Answer:
2 moles of Substance B
Explanation:
Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)
Therefore 12.04 × 10²³/ 6.02× 10²³ = 2 mole of Substance B
Answer:
The answer is "
".
Explanation:
calculating the moles in
Eqution:
![CH_4 +H_2O \to 3H_2+ CO \ (g)](https://tex.z-dn.net/?f=CH_4%20%2BH_2O%20%5Cto%20%203H_2%2B%20CO%20%5C%20%28g%29)
Calculating the amount of
produced:
![= 12.9 \ mol CH_4 \times \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2](https://tex.z-dn.net/?f=%3D%2012.9%20%5C%20mol%20CH_4%20%5Ctimes%20%20%5Cfrac%7B3%20%5C%20mol%20%5C%20H_2%20%7D%7B1%20%5C%20mol%20%5C%20CH_4%7D%5Ctimes%20%5Cfrac%7B2.016%20g%20H_2%7D%7B1%20%5C%20mol%20%5C%20H_2%7D%5C%5C%5C%5C%3D%2078%20%5C%20g%20%5C%20H_2%20%5C%5C%5C%5C%3D%200.078%20%5C%20kg%20%5C%20H_2)
So, the amount of dihydrogen produced = ![0.078 \frac{kg}{s}](https://tex.z-dn.net/?f=0.078%20%5Cfrac%7Bkg%7D%7Bs%7D)