Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Answer:
Big Bang or Phased Approach – ERP Implementation strategies include Big Bang, Phased, Hybrid, and Parallel Adoption. Each organization requirements are different and as such, the project management method is itself evolving using PPM, SCRUM, and DevOps.
Answer:
b. an e-mail
Explanation:
Based on the scenario being described within the question it can be said that the best electronic communication tool in this scenario would be an e-mail. Using e-mails you would be able to send detailed communication messages to all of the individuals that need to read that message in one e-mail. Thus allowing for fast and clear communication between all relevant parties. Both podcasts and Wiki's are used for providing information to clients, or the target audience but not for sharing info within the company.
Answer:
Follows are the method definition to this question:
void printArray(int arrayToPrint[], int arraySize) //defining a method printArray that accepts two array in its parameters
{
for (int j = 0; j < arraySize; j++)//defining for loop print Serial numbers
{
Serial.print("[");//use print method to print square bracket
Serial.print(j);//use print method to print Serial numbers
Serial.print("]: ");//use print method to print square bracket
Serial.println(arrayToPrint[j]);//printing array value
}
}
Explanation:
In the above code, a method "printArray" is declared that holds two arrays "arrayToPrint and arraySize" as a parameter, and inside the method is used for loop to print the values.
In the loop, first, it uses the square bracket to print the serial number and in the last step, it prints array values.
This is a tough question. I’m not sure if I’ll get it right but I’ll try.
Data structures used for file directories typically have a hierarchical tree structure, referred to as a directory structure. The tree has a root directory, and every file in that system has a unique path.
The simplest method of implementing a directory is to use a linear list of file names with pointers to the data blocks. But another way that you can format a file directory is by using a hash table. With this method, the linear list stores the directory entries, but a hash data structure is also used. The hash table takes a value computed from the file name and return the pointer to the file name any linear list.
So I think it’s C. But I’m not 100% sure.
I hope that helps.
