All categories

3 years ago

The area of the triangle shown is 40.0 cm2.

Mathematics

1 answer:

kompoz [17]3 years ago

4 0

Answer:

The height of the triangle is 6.4cm

Step-by-step explanation:

- If the triangle has a side that measures 12.5cm, it means that two of its sides are equal in length.

Which is equivalent to the description of an isosceles triangle.

To find the height, use the equation of the area.

Area = (Base * height) / 2

- We know the value of the area and its shorter side that could be the base.

40cm = (12.5 cm * h) / 2

- Clearing the height would give that:

80cm / 12.5cm = h

h = 6.4cm

The height of the triangle is 12.5cm

You might be interested in

Marc has 45 books on his bookshelf, and Corinna has 61. If Marc buys 4 new books each month and Corinna buys 2 new books each mo

luda_lava [24]

Call x as the number of months that Marc and Corinna have the same number of book.
45 +4x= 61 +2x
4x- 2x= 61-45
2x= 16
x= 8

7 0

2 years ago

The triangle and the trapezoid have the same area. Base b2 is twice the length of base b1. What are the lenghts of the bases of

Sati [7]

Answer:

<h2>The lengths of the bases of the trapezoid:</h2><h2>42/h cm and 84/h cm.</h2>

Step-by-step explanation:

The formula of an area of a triangle:

$A=\dfrac{bh}{2}$

b - base

h - height

We have b = 21cm, h = 6cm.

Substitute:

$A=\dfrac{(21)(6)}{2}=63\ cm^2$

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

We have b₁ = 2b₂, therefore b₁ + b₂ = 2b₂ + b₂ = 3b₂.

The area of a triangle and the area of a trapezoid are the same.

Therefore

$\dfrac{3b_2}{2}\cdot h=63$ multiply both sides by 2

$3b_2h=126$ divide both sides by 3

$b_2h=42$ divide both sides by h

$b_2=\dfrac{42}{h}$

$b_1=2b_2\to b_1=2\cdot\dfrac{42}{h}=\dfrac{84}{h}$

8 0

2 years ago

Read 2 more answers

Helooo can some one help me please

oee [108]

The answer is 184. 2711
Round it off is 184
Hope that helped :D

5 0

3 years ago

How to solve this problem step by step. Make brainliest answer if its done. Please

sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

$\frac{y2 - y1}{x2 - x1}$

<h3>Gradient of DE: </h3>

SUB IN COORDINATES OF D AND E

$\frac{1 - 2}{ - 1 - 2}$

therefore the gradient of DE is 1/3.

<h3>Gradient of BC:</h3>

SUB IN COORDINATES OF B AND C

 $\frac{ - 2 - 0}{ - 3 - 3}$ 

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

6 0

3 years ago

-5(x+7)<10. What does x equal?

gulaghasi [49]

Answer:

X>-9

Step-by-step explanation:

Distribute

-5x-35<10

add 35 on both sides

-5x<45

Divide -5 on both sides and flip the sign since your dividing by a NEGATIVE number

x>-9

4 0

3 years ago

Read 2 more answers