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Ksivusya [100]
3 years ago
12

Can anyone help me with this? Reduce the fraction

Mathematics
1 answer:
Elden [556K]3 years ago
3 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{-20t^5u^2v^3}{48t^7u^4v}\implies \cfrac{-20}{48}\cdot \cfrac{t^5u^2v^3}{t^7u^4v^1}\implies \cfrac{-5}{12}\cdot \cfrac{v^3v^{-1}}{t^7t^{-5}u^4u^{-2}}\implies \cfrac{-5}{12}\cdot \cfrac{v^{3-1}}{t^{7-5}u^{4-2}} \\\\\\ \cfrac{-5}{12}\cdot \cfrac{v^2}{t^2u^2}\implies \cfrac{-5v^2}{12t^2 u^2}

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Magnetism: So I need help on this question but please explain how you got the answer so I can learn and better provide evidence
kramer

Step-by-step explanation:

A) as you can see there is no current flowing in a bar magnet so (incorrect)

B) Lines of magnetic field is going in A-->B direction so it have starting and ending points.(incorrect)

C) Yes whenever a magnetic object is placed near the another magnetic object they either attract or repell so they have a force in a form of push and pull [correct]

D)No because magnetic field lines goes from North--> South so A is the South pole [ incorrect]

E) Yes it will point always towards North pole of the magnet [correct]

F) yes it depends upon the density of field lines[correct]

G)No the near the magnet is it becomes more stronger as compared to magnet kept far.(incorrect)

So option C E F are correct

Hope this helps

Have a great day

7 0
2 years ago
The slope of the line below is -3. Which of the following is the point-slope
Anna [14]

Given:

The slope of the line is -3.

The line passes through the point (2,-2).

To find:

The point-slope form of the line.

Solution:

Point slope form: If a line passes through the point (x_1,y_1) with slope m, then the point-slope form of the line is:

y-y_1=m(x-x_1)

The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:

y-(-2)=-3(x-2)

y+2=-3(x-2)

Therefore, the required point slope form of the given line is y+2=-3(x-2).

5 0
3 years ago
Please help me rn!!!!!
neonofarm [45]
The answer is A, the first one :)
3 0
2 years ago
Find the solution set of the quadratic equation over the set of complex numbers.
blagie [28]
Step 1: Multiply 5x2 = 10 so the equation after the first step should look like this 10 + 12x + 8 = 0.

Step 2: Subtract 10 from the 8 and the number by itself cause whatever you do to one side you must do to the other. so the equation should look like this after the second step 12x + -2 = 0 because we subtracted the 10 and the 8.

Step 3: Now we must add the 2 to both sides because we have to do the inverse operation in this problem so once we've done this it should end up looking like this after the 3rd step 12x = 2 because the 2 was a negative.

Step 4: the final step we must divide since an anytime we have a number next to a variable it means multiply but since were using order of operations we have to do the opposite/inverse operation in this problem and we would divide 12 by 2 and get our final answer as x = -6 because the 12 would cancel itself out leaving us with 2 divided by 12 which is 0.16 or -6 depending on if you want it simplified or not the simplified answer would be 0.16 and the non simplified version would be -6
4 0
3 years ago
Read 2 more answers
Simplify the algebraic expression by combining like (or similar) terms.<br> -7x - 8y- 5x - 6y
stira [4]

Answer:

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Step-by-step explanation:

First I would move them side by side so I can see it better so:

-7x - 5x - 8y - 6y

now combine the x values together and the y values together:

-12x - 14y

7 0
3 years ago
Read 2 more answers
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