Question

(m^3p^5divide by n^7)x(m^2n^0p^3divdie bye m^4n^2)^3

Answer 1

Convert division to exponent neative
also, n^0=1 so get rid of that nonesense
also we have m^2/m^4 so we are left wiht 1/(m^2) or m^-2

so
$(m^3p^5n^{-7})(p^3m^{-2}n^{-2})^3$=
$(m^3p^5n^{-7})((p^3)^3)((m^{-2})^3)((n^{-2})^3)$=
$(m^3p^5n^{-7})(p^9)(m^{-6})(n^{-6})$=
$(m^3)(p^5)(n^{-7})(p^9)(m^{-6})(n^{-6})$=
$(m^{-3})(p^{14})(n^{-13})$=
$\frac{p^{14}}{m^3n^{13}}$