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3 years ago

13

Find an equation of the line perpendicular to the graph of 15x-5y=7 that passes through the point at (0,-4)

2 answers:

vichka [17]3 years ago

7 0

Answer:

b. y=-1/3x-4

Step-by-step explanation:

shusha [124]3 years ago

4 0

Perpendicular lines have slopes that multiply to -1
get into y=mx+b form
minus 15x both sides and divide by -5
y=3x-7/5
slope is 3

3 times what=-1?
what=-1/3

so the slope is -1/3

so
y=-1/3x+b
we use the point (0,-4)
x=0 and y=-4
-4=-1/3(0)+b
-4=b

y=(-1/3)x-4 is da equation

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