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Dvinal [7]
3 years ago
7

What is the value of 2/3^-4

Mathematics
1 answer:
Reptile [31]3 years ago
8 0

Answer:

\frac{16}{49}

Step-by-step explanation:

To solve problems like this, we need to multiply the base ,\frac{2}{3} , the amount of times as the exponent, 4.

Essentially, the equation is \frac{2}{3} x \frac{2}{3}  x \frac{2}{3}  x \frac{2}{3} .

The product would be \frac{16}{49}.

Now we can't forget that the exponent is a negative. But because the exponent is an even number, we don't need to worry about that.

Hope this helped :)

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If the dimensions of the following cylinder are doubled, what factor will the surface area change by?
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Answer:

probably 2 or 4

Step-by-step explanation:

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3 years ago
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Natalka [10]

9514 1404 393

Answer:

  • 4/13 h ≈ 0.308 h
  • 22 9/13 km ≈ 22.7 km

Step-by-step explanation:

Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...

  t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h

They will pass each other after 4/13 hours, about 18 minutes 28 seconds.

__

In that time, Mary will have increased her distance from Hall Beach by ...

  d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km

Her distance from Hall Beach when she passes Amaruk will be ...

  15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach

6 0
3 years ago
Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k​
masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

2

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

We find the discriminant,

D=(1-k)^2-4(1)(k-3)D=(1−k)

2

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

2

−2k−4k+12

D=k^2-6k+13D=k

2

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0
3 years ago
Answer correct for brainliest and also get a thanks !:-) you don't have to answer B.
skelet666 [1.2K]
I hope this helps you

7 0
3 years ago
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