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grin007 [14]
2 years ago
9

#3 and 5 please I don’t understand how to get them

Mathematics
1 answer:
denpristay [2]2 years ago
6 0

Answer:

im bad with this kinda thing, just guess and start praying, goodluck

Step-by-step explanation:

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Please help!<br><br> For what value of x must ABCD be a​ parallelogram?<br><br> x=?
Vlad1618 [11]

Answer:

x=3

Step-by-step explanation:

For a shape to be a parallelogram, the angles that are across from one another have to be equal.

We can now find x by making both equations equal to each other and solving.

11x+1=13x-5

Solve.

11x+1=13x-5\\6=2x\\x=3

4 0
3 years ago
eddie is practicing wind sprints during summer break. hes able to run 72 meters in 12 seconds if d represents distance and t rep
kkurt [141]
The ratio is 12:72............

5 0
3 years ago
Find the average rate of change over the interval [-1,2] (from x = -1 to x = 2) for the graph below
Lyrx [107]

Hello!

Find the coordinate where x = -1:

At x = -1, y = 1, so the coordinate is (-1, 1).

Find the coordinate where x = 2:

At x = 2, y = -2, so the coordinate is (2, -2).

Find the rate of change between the points using the slope formula:

slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Plug in the coordinates above:

slope = \frac{-2-1}{2-(-1)}

Simplify:

slope = \frac{-3}{3} = -1

Thus, the rate of change between the points is -1.

8 0
2 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
Can someone help me with this?
tatiyna
Yes because PROPORTIONAL means the lines start on the axis which is the zero and it also has to be in a even line so yes it is proportional
6 0
3 years ago
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