Answer:
c. 108.4
Step-by-step explanation:
cos theta = (u dot v)/ (||u|| ||v||)
where dot stands for dot product and || || is the magnitude
u = (1,5) v= (7,-4)
u dot v = (1*7 + 5*-4) = 7-20 = -13
||u|| = sqrt( 1^2 +5^2) = sqrt(1+25) = sqrt(26)
||v|| = sqrt(7^2 + (-4)^2) = sqrt(49+16) = sqrt(65)
cos theta = -13/ sqrt(26) sqrt(65)
cos theta = -13 /sqrt(1690)
theta = arccos (-13/sqrt(1690))
theta = 108.43
4z>-6
divide by 4
z>-6/4
z>-3/2
x+19<= -5
subtract 19 from both side
x<= -24
If line segment EF is 28 and F is halfway through the line, then segment EF will be half of 28. So segment EF=14
Whooh
SA=4pir²
take derivitive
dSA/dt=8pir dr/dt
and do the volume as well
V=(4/3)pir³
dV/dt=4pir² dr/dt
we need to solve for dV/dt
to do taht we need dr/dt
so
dSA/dt=8pir dr/dt
given dSA/dt=3pi cm/sec
r=2
3pi=8pi2 dr/dt
3=16 dr/dt
3/16=dr/dt
now do the volume
dV/dt=4pir² dr/dt
r=2
dr/dt=3/16
dV/dt=4pi2² (3/16)
dV/dt=16pi(3/16)
dV/dt=3pi
nice
the volume of the sphere is decreasing at 3pi cm/sec as well
Answer:
read your username :)
Step-by-step explanation: